Complete Question
You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?
Answer:
The pK_a value is
Explanation:
From the question we are told
The volume of base is 
The pH of solution is 
The concentration of the acid is 
From the pH we can see that the titration is between a strong base and a weak acid
Let assume that the the volume of acid is 
Generally the concentration of base

Substituting value


When 13mL of the base is added a buffer is formed
The chemical equation of the reaction is

Now before the reaction the number of mole of base is
![No \ of \ moles[N_B] = C_B * V_B](https://tex.z-dn.net/?f=No%20%5C%20of%20%5C%20moles%5BN_B%5D%20%20%3D%20%20C_B%20%2A%20V_B)
Substituting value

Now before the reaction the number of mole of acid is

Substituting value


Now after the reaction the number of moles of base is zero i.e has been used up
this mathematically represented as

The number of moles of acid is


The pH of this reaction can be mathematically represented as
![pH = pK_a + log \frac{[base]}{[acid]}](https://tex.z-dn.net/?f=pH%20%20%3D%20pK_a%20%2B%20log%20%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D)
Substituting values

Answer:
Precipitate
Explanation:
A precipitate is a solid formed from a chemical solution
The structure of the alkyl bromides used in a malonic ester synthesis of ethyl 2-methyl-4-pentenoate.
Ethyl 2-methyl-4-pentenoate by Malonic ester synthesis.
The alkylation of diethyl malonate or a related ester of malonic acid at the carbon alpha (immediately next) to both carbonyl groups, followed by conversion to a substituted acetic acid, characterizes the chemical reaction known as the malonic ester synthesis.
As a result, it is evident from the structure of ethyl 2-methyl-4-pentenoate that ethyl and methyl bromides are the alkyl bromides employed.
To learn more about Malonic ester synthesis refer here:
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1 mole is 6.02x 10^23 molecules
3 * 6.02*10^23 =1.806*10^24 molecules
Answer:
We need 0.095 moles of ethanol
Explanation:
Step 1: Data given
Number of moles water = 0.095 moles
Step 2: The balanced equation
CH3CH2OH + O2 ⇒ H2O + CH3COOH
Step 3: Calculate moles of ethanol
For 1 mol ethanol we need 1 mol oxygen to produce 1 mol water and 1 mol acetic acid
For 0.095 moles water, we need 0.095 moles ethanol and 0.095 moles oxygen
We need 0.095 moles of ethanol