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algol13
4 years ago
8

A mixture of pepper and water is a suspension because ________ HELPPPP

Chemistry
1 answer:
malfutka [58]4 years ago
7 0
It doesn't because pepper does not dissolve
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How can the partial charges be shown in a polar covalent molecule?
joja [24]
Δ, namely δ− or δ+. Partial charges<span>are created due to the asymmetric distribution of electrons in chemical bonds. For example, in a </span>polar covalent<span> bond like HCl, the shared electron oscillates between the bonded atoms.</span>



Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
7 0
3 years ago
Calculate the empirical formula of a compound that is 42.9% Carbon and 57.1% Oxygen.
Marrrta [24]

Answer:

CO.

Explanation:

Assuming the given percentages are by mass, we can solve this problem via imagining we have <em>100 g of the compound</em>, if that were the case we would have:

  • 42.9 g of C
  • 57.1 g of O

Now we <u>convert those masses into moles</u>, using the<em> elements' respective molar masses</em>:

  • 42.9 g of C ÷ 12 g/mol =  3.57 mol C
  • 57.1 g of O ÷ 16 g/mol =  3.58 mol O

As the number of C moles and O moles is roughly the same, the empirical formula for the compound is <em>CO</em>.

4 0
3 years ago
Calculate the enthalpy of combustion, δh∘comb, for c6h14. you'll first need to determine the balanced chemical equation for the
Vedmedyk [2.9K]
<span>Answer: Enthalpy Change = (6 x -393.5) + (7 x -285.8) - (-204.6) + (19/2) 0.....??? like.. (6 x Enth CO2) + ( 7 x Enth H2O) - (Enth C6H14) + (19/2) Enth O2</span>
3 0
4 years ago
Calculate the change in entropy when 1.00 kg of water at 100 ∘C is vaporized and converted to steam at 100 ∘C. Assume that the h
andrew11 [14]

Answer : The change in entropy is 6.05\times 10^3J/K

Explanation :

Formula used :

\Delta S=\frac{m\times L_v}{T}

where,

\Delta S = change in entropy = ?

m = mass of water = 1.00 kg

L_v = heat of vaporization of water = 2256\times 10^3J/kg

T = temperature = 100^oC=273+100=373K

Now put all the given values in the above formula, we get:

\Delta S=\frac{(1.00kg)\times (2256\times 10^3J/kg)}{373K}

\Delta S=6048.25J/K=6.05\times 10^3J/K

Therefore, the change in entropy is 6.05\times 10^3J/K

5 0
3 years ago
An inflated balloon contains X air molecules.After some time the volume of the balloon is found to be the half at the same tempe
sladkih [1.3K]

Answer:

See explanation

Explanation:

According to Avogadro's law, the volume of a given mass of gas is directly proportional to the number of molecules of gas present at constant temperature and pressure.

Hence; V1/n1 = V2/n2

The implication of this is, if there were X molecules present and the volume of the balloon is halved, the number of molecules of gas present is also halved. So, we now have X/2 number of gas molecules present in the balloon.

This is in accordance with the statement of Avogadro's law.

8 0
3 years ago
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