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3 years ago

9

If a longitudinal wave passes a specific point seven times per second, and the distance between wave rarefaction points is 2 met

ers, what is the speed of the wave?

1 answer:

zavuch27 [327]3 years ago

4 0

Answer: 14 m/s

Explanation:

The speed $S$ of a sound wave is given by the following equation:

$S=\lambda f$

Where:

$\lambda=2 m$ is the wavelength of the sound wave

$f=7 times/s=7 Hz$

$S=(2 m)(7 Hz)$

Hence:

$S=14 m/s$

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water in a cup and a kettle can have the same temperature even though the quantities are different . give reasons

jekas [21]

Answer:

The reason is because both are exposed to a virtually infinite heat sink, due to the virtually infinite mass and of the surrounding environment, compared to the sizes of either the cup or the kettle such that the equilibrium temperature, $T_{(equilibrium)}$ reached is the same for both the cup and the kettle as given by the relation;

$\infty M_{(environ)} \times c_{(environ)} \times (T_2 - T_1) = m_{1} \times c_{(water)} \times (T_3 - T_2) + m_{2} \times c_{(water)} \times (T_4 - T_2)$

Due to the large heat sink, T₂ - T₁ ≈ 0 such that the temperature of the kettle and that of the cup will both cool to the temperature of the environment

Explanation:

4 0

3 years ago

A 5-m steel beam is lowered by means of two cables unwinding at the same speed from overhead cranes. As the beam approaches the

ArbitrLikvidat [17]

Answer:

a) The angular acceleration of the beam is 0.5 rad/s²CW (direction clockwise due the tangential acceleration is positive)

b) The acceleration of point A is 3.25 m/s²

The acceleration of point E is 0.75 m/s²

Explanation:

a) The relative acceleration of B with respect to D is equal:

$a_{B} =a_{D} +(a_{B/D} )_{n} +(a_{B/D} )_{t}$

Where

aB = absolute acceleration of point B = 2.5 j (m/s²)

aD = absolute acceleration of point D = 1.5 j (m/s²)

(aB/D)n = relative acceleration of point B respect to D (normal direction BD) = 0, no angular velocity of the beam

(aB/D)t = relative acceleration of point B respect to D (tangential direction BD)

$a_{B} =a_{D} +(a_{B/D} )_{t}$

$2.5j=1.5j +(a_{B/D} )_{t}\\(a_{B/D} )_{t}=j=1m/s^{2}$

We have that

(aB/D)t = BDα

Where α = acceleration of the beam

BDα = 1 m/s²

Where

BD = 2

$2\alpha =1\\\alpha =0.5rad/s^{2}CW$

b) The acceleration of point A is:

$a_{A} =a_{D} +(a_{A/D} )_{t}$

(aA/D)t = ADαj

$a_{A} =a_{D} +AD\alpha j\\a_{A}=1.5j+(3.5*0.5)j\\a_{A}=3.25jm/s^{2}$

The acceleration of point E is:

(aE/D)t = -EDαj

$a_{E} =a_{D} -ED\alpha j\\a_{E}=1.5j-(1.5*0.5)j\\a_{E}=0.75jm/s^{2}$

7 0

3 years ago

Can someone please help me ASAP please!

natulia [17]

It would be D (hoping the picture you posted is what you needed help with

8 0

3 years ago

Magnesium (Mg) has 12 protons and an atomic mass of 24. How many neutrons does magnesium have?

JulijaS [17]

An atom is made up of three different particles, which are proton, neutron and electron. The proton and the neutron are located in the nucleus of the atom and they make up mass of the atom. The electron orbit around the nucleus. The proton is positively charged while the electron is negatively charged, thus, for the atom to remain neutral, the number of proton and electron in an atom must be equal. The neutron has no charge.
The atomic mass of an element = number of proton + number of neutron
Atomic mass of magnesium= 24
Number of proton = 12
Therefore, number of neutron = 24 - 12 = 12.
Thus, the number of neutron = 12.

5 0

3 years ago

Read 2 more answers

A Pitot-static tube is mounted on a 2.5 cm pipe where oil (???? = 860 kg/m3, ???? = 0.0103 kg/m·s) is flowing. The Pitot tube is

emmasim [6.3K]

Answer:

$\dot{V}=0.0733 \,m^3.s^{-1}$

Explanation:

Given:

density, $\rho=860\,kg.m^{-3}$

diameter of the pipe, $d=2.5\times 10^{-2}m$

pressure difference, $\Delta P=95.8\times 10^{5}\,Pa$

In case of pitot tube, the velocity is given by:

$v=\sqrt{\frac{2.\Delta P}{\rho} }$

$v=\sqrt{\frac{2\times 95.8\times 10^{5}}{860} }$

$v=149.26\,m.s^{-1}$

Now we know that volumetric flow rate is given as:

$\dot{V}=a.v$

where :

a= cross sectional area of the pipe

v= velocity of flow

$\dot{V}=(\pi\times \frac{(2.5\times 10^{-2})^2}{4} ) \times 149.26$

$\dot{V}=0.0733 \,m^3.s^{-1}$

4 0

3 years ago