a train leaves a station heading east at 50 mph from that same station a car drives north at a speed of 30mph after 3 hours how
1 answer:
Answer:
d = 175 miles
Explanation:
Train is moving towards East with constant speed of 50 mph
While car is moving at speed of 30 mph
so after t = 3 hours
the distance moved by the train is given as
at the same time the distance moved by the car is given as
now we know that both car and train is moving perpendicular to each other
So the distance between them after t = 3 hours is given as
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Answer:
vcyl / vsph = 1.05
Explanation:
- The kinetic energy of a rolling object can be expressed as the sum of a translational kinetic energy plus a rotational kinetic energy.
- The traslational part can be written as follows:
- The rotational part can be expressed as follows:
- where I = moment of Inertia regarding the axis of rotation.
- ω = angular speed of the rotating object.
- If the object has a radius R, and it rolls without slipping, there is a fixed relationship between the linear and angular speed, as follows:
- For a solid cylinder, I = M*R²/2 (4)
- Replacing (3) and (4) in (2), we get:
- Adding (5) and (1), we get the total kinetic energy for the solid cylinder, as follows:
- Repeating the same steps for the spherical shell:
- Since we know that both masses are equal each other, we can simplify (6) and (9), cancelling both masses out.
- And since we also know that both objects have the same kinetic energy, this means that (6) are (9) are equal each other.
- Rearranging, and taking square roots on both sides, we get:
- This means that the solid cylinder is 5% faster than the spherical shell, which is due to the larger moment of inertia for the shell.
Refer to the attachment
