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ella [17]
4 years ago
5

a train leaves a station heading east at 50 mph from that same station a car drives north at a speed of 30mph after 3 hours how

far apart are the two vehicles?
Physics
1 answer:
Alecsey [184]4 years ago
8 0

Answer:

d = 175 miles

Explanation:

Train is moving towards East with constant speed of 50 mph

While car is moving at speed of 30 mph

so after t = 3 hours

the distance moved by the train is given as

d_1 = vt

d_1 = (50)(3) = 150 miles

at the same time the distance moved by the car is given as

d_2 = 30(3) = 90 miles

now we know that both car and train is moving perpendicular to each other

So the distance between them after t = 3 hours is given as

d= \sqrt{d_1^2 + d_2^2}

d = \sqrt{150^2 + 90^2}

d = 175 miles

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Can you tell it in pounds
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3 years ago
Suzie (of mass 42 kg) is roller-blading down the sidewalk going 32 miles per hour. She notices a group of workers down the walkw
Allisa [31]

Answer:

a) Suzie’s average acceleration = -6.46 m/s²

b) Force exerted to stop Suzie = 271.52 N

Explanation:

a) We have equation of motion, v = u + at

     Final velocity, v = 0 m/s

     Initial velocity, u = 32 mph = 14.22 m/s

     Time, t =2.2 s

Substituting

     0 = 14.22 + a x 2.2

     a = -6.46 m/s²

Suzie’s average acceleration = -6.46 m/s²

b) Mass of Suzie = 42 kg

   Force = Mass x Acceleration

   F = Ma

   F = 42 x -6.46 =-271.52 N

   Force exerted to stop Suzie = 271.52 N

5 0
3 years ago
Work out the area of a rectangle with base, b=20mm and perimeter, p=50mm
Korvikt [17]

Answer:

100mm²

Explanation:

the other side: (50 - 20 × 2) ÷ 2 = 5

5 × 20 = 100

7 0
3 years ago
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Give two example of Pseudoscience?
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Answer:

1. astrology

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Explanation:

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3 years ago
Aluminum wire 1.00 mm in radius is to be used to construct a solenoid 15.0 mm in radius so that the magnitude of the magnetic fi
Leto [7]

To solve this problem we will proceed to use the equations given for the calculation of the resistance, in order to find the radius of the cable. Once the length is found we can find the number of turns of the solenoid and finally the net length of it

The resistance of the wire is

R= \frac{\rho L}{A}

\rho= Resistivity

L = Length

A = Cross-sectional Area

That can be also expressed as,

R = \frac{\rho L}{\pi r^2}

Rearranging the equation for the length of the wire we have

L= \frac{R\pi r^2}{\rho}

L= \frac{3\Omega \pi(1*10^{-3})}{2.655*10^{-8}\Omega \cdot m}

L = 354.8m

The number of turns of the solenoid is

N = \frac{L}{2\pi r} \rightarrow Denominator is equal to the circumference of the loop

N = \frac{354.8}{2\pi(15*10^{-3})}

N = 3766

Finally the Length of he solenoid is

l = N (\phi)

Where \phi is the diameter of wire

l = N (2r)

l = (3766)(2*(1*10^{-3}))

l = 7.532m

Therefore the length of the solenoid is 7.532m

7 0
4 years ago
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