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malfutka [58]
3 years ago
14

Do i become a professional astrophysicist after getting PhD in Astrophysics ? Or will i be a postdoc research student i mean wil

l i be practicing under another researcher ? Will i get the correct salary just after finishing PhD ?
Physics
1 answer:
DaniilM [7]3 years ago
4 0

Most jobs in Astrophysics require a PhD. That's why that's what I'll be going for when I start my degree in it.

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Ignacio and Velvet walk eastward with a speed of 8 m/s. If it takes them 7.5 minutes to walk to the store, how far in meters hav
ryzh [129]

Answer:

They walk 3,600 meters

Explanation:

7.5 minutes = 450 seconds.

Because they are walking at 8 meters per 1 second, multiply 8 by 450.

= 3600m

7 0
3 years ago
Read 2 more answers
Match the terms to the correct descriptions. Question 1 options:
faust18 [17]
1) Refraction
2)Reflection
3)Concave
4)Convex

I took the test and got this right so you can believe me :)
Hope this helps
4 0
3 years ago
Read 2 more answers
The drag force on a falling coffee filter can be modeled as a linear function with respect to velocity, F⃗ D =−bv, where b is a
nordsb [41]

Newton's second law and graphical analysis allow us to find the correct answer for the measure of the constant b is:

    D) Stack several filters to change the mass measure the acceleration of the system.

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the bodies.  

         ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

They indicate that the drag force on the filters is

         F = - b v

Where b is a positive constant that depends on the shape and area of ​​the filter and v is the speed of the filter.

Let's write Newton's second law.

         W - fr  = ma

         W -bv  = ma

         

In the experiment the students indicate that they can measure the position, velocity and acceleration of the body.

Based on the above, if we place several filter weights and measure their speed and acceleration in each case, we can make a graph of velocity versus acceleration, we can take the value of the constant b from the slope.

Let's analyze the different answers:

A) False. The constant b depends on the shape of the filter therefore it must be kept constant.

B) False. The constant depends on the area, so it must be kept constant.

C) May be. In this case, since we have the terminal velocity, the acceleration is zero, Newton's second law remains.

                    B v - W = 0

                    b = \frac{W}{v}  

The problem with the method is the difficulty of measuring the compression terminal velocity.

D) True. According to the discussion of the velocity versus acceleration. graph, the constant b is equal to the slope of the graph.

E) May be. The problem with this method is finding a reliable value for the terminal velocity.

In conclusion, using Newton's second law and graphical analysis we can find the correct answer for the measure of the constant b is:

 D) Stack several filters to change the mass measure the acceleration of the system.

Learn more here:  brainly.com/question/2441565

6 0
2 years ago
two objects are thrown from the top of a tall building and experience no appreciable air resistance. one is thrown up and the ot
Iteru [2.4K]

Answer:

The two objects are traveling at the same speed.

Explanation:

Neglecting air resistance, an object that is thrown up from the top of a tall building has the same speed as the second object thrown down from the top of the same tall building since the initial speed is the same.

The object thrown up is not traveling faster neither is the object thrown down traveling faster.  

Therefore, the two objects will have the same speed when they hit the ground but their time of landing might be different.

3 0
3 years ago
Read 2 more answers
A charged sphere with 1 × 10 8 units of negative charge is brought near a neutral metal rod. The half of the rod closer to the s
jeyben [28]

Answer:

-4*10⁴ units.

Explanation:

As the metal rod was initially neutral (which means that it has the same quantity of positive and negative charges), after being close to the charged sphere, as charge must be conserved, the total charge of the metal rod must  still remain to be zero.

So, if due to the influence of the negative charge in the sphere, the half of the road closer to the sphere has a surplus charge of +4*10⁴ units, the charge on the half of the rod farther from the sphere must be the same in magnitude but of the opposite sign, i.e., -4*10⁴ units.

5 0
3 years ago
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