y = y0 +v0*t +0.5at^2
where y0 = initial vertical position = 22m
y = final vertical position = 0m
v0 = initial vertical velocity = 0 m/s
a = acceleration = -9.8 m/s^2
t = time in seconds
0 = 22 +0*t + 0.5(-9.8)t^2
t^2 = 22/4.9 = 4.49 s^2
t = 2.12 s
So it traveled 35m in 2.12 s
the horizontal distance traveled is determined by:
x = x0 +v0*t +0.5at^2
but here a in the horizontal direction is 0 m/s^2
and v0 is in the velocity in the horizontal direction in this equation
35 m = 0 +v0*t
35 m = v0(2.12 s)
v0 = 16.5 m/s
So the ball was kicked 16.5 m/s in the horizontal direction
Answer:
The voltage is
Explanation:
From the question we are told that
The voltage of the battery is
The capacitance of the capacitor is
The resistance of the resistor is
The time taken is
Generally the voltage of a charging charging capacitor after time t is mathematically represented as
Here is the voltage of the capacitor when it is fully charged which in the case of this question is equivalent to the voltage of the battery so
Runner A is faster than runner B
Runner B has a head start
After the collision, the momentum of each cart has the same magnitude as it had before the collision, but in the opposite direction.