Answer:
Final speed, v = 1.25 m/s
Explanation:
Given that,
Mass of skater A, 
Initial speed of skater A,
(x axis)
Mass of skater B, 
Initial speed of skater B,
(y axis)
It is mentioned that the two skaters collide and cling together. It is case of inelastic collision in which momentum remains conserved. Let V is the final speed of the couple. It is given by :





So, the final speed of the couple is 1.25 m/s. Hence, this is the required solution.
The effiency of a machine is
(output work or energy) / (input work or energy) .
For the system described in the question, that's
(123 J) / (150 J) = 0.82 = 82% .
Answer:
The current flowing through the outer coils is
Explanation:
From the question we are told that
The number of turn of inner coil is 
The radius of inner coil is 
The current flowing through the inner coil is 
The number of turn of outer coil is 
The radius of outer coil is 
For net magnetic field at the common center of the two coils to be zero the current flowing in the outer coil must be opposite to current flowing inner coil
The magnetic field due to inner coils is mathematically represented as

The magnetic field due to inner coils is mathematically represented as

Now for magnetic field at center to be zero

So

=> 

250m good luck onnur test
Answer:
y₀ = 1020.3 m
Explanation:
This is a projectile launching exercise, in this case as the package is released its initial vertical velocity is zero.
y = y₀ +
t - ½ g t²
when it reaches the ground its height is zero
0 = y₀ + 0 - ½ g t²
y₀ = ½ g t²
let's calculate
y₀ = ½ 9.8 14.43²
y₀ = 1020.3 m