Calculate the wavelength λ and the frequency f of the photons that have an energy of E photon = 2.32 × 10 − 19 J. Ephoton=2.32×1
1 answer:
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Answer:
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Answer: has wavelengths that are longer than visible light
Explanation: Electromagnetic spectra comprises of different electromagnetic waves which are arranged in order of increasing wavelengths or decreasing energies.
In order from highest to lowest energy, the waves are arranged as: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.
E= energy
h= planck's constant
c= velocity of light
= wavelength
As wavelength and energy are inversely related, the wave having higher wavelengths will be lowest in energy. Thus as infrared radiation have lower energy as compared to visible radiation. Thus infrared radiation have higher wavelength as compared to visible radiation.
Answer:
a) 35 kPa
d) 140 N
c) 1) Increasing the brake fluid pressure
2) Increasing the slave piston surface area.
Explanation:
The parameters given are;
a) Force applied to the master cylinder piston = 28 N
Cross sectional area of the master cylinder piston = 8 cm² = 8 × 10⁻⁴ m²
The pressure P on the brake fluid is given by the formula for pressure as follows;
The pressure on the brake fluid, P, produced by the master cylinder piston = 35,000 Pa = 35 kPa
b) Given that the area of the slave piston = 40 cm² = 0.004 m², we have from the formula for pressure, P;
Therefore;
Applied force on the slave piston = 4 × 10⁻³ m² × 35,000 N/m² = 140 N
c) The force, F produced by the slave cylinder piston is given by the relation;
F = Pressure × Area
Therefore, the two ways of increasing the force produced by the slave cylinder piston is as follows;
1) Increasing the pressure in the brake fluid by increasing the force exerted by the master cylinder piston
2) Increasing the surface area of the slave piston.