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Tju [1.3M]
3 years ago
14

Calculate the wavelength λ and the frequency f of the photons that have an energy of E photon = 2.32 × 10 − 19 J. Ephoton=2.32×1

0−19 J. Use c = 3.00 × 10 8 m/s c=3.00×108 m/s for the speed of light in a vacuum.
Physics
1 answer:
klasskru [66]3 years ago
4 0

Answer:

Frequency =3.5×10^14hertz

Wavelength = 8.6×20^-7m

Explanation:

Energy of photon is expressed as;

E = hf where;

h is the Planck constant

f is the frequency of the photons

From the formula f = E/h

Given E = 2.32 × 10^ − 19 J

h = 6.63×10^-34Js

f = 2.32×10^-19/6.63×10^-34

f = 0.35×10^(-19+34)

f = 0.35 × 10^15

f = 3.5×10^14hertz

To get the wavelength, we will use the relationship:

f = c/λ

λ = c/f

Given c = 3×10^8m/s

f = 3.5×10^14hertz

λ = 3×10^8/3.5×10^14

λ = 0.86×10^-6m

λ = 8.6×20^-7m

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A proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 2.50 × 1012 m/s2 in a machine. If the proton h
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Answer:

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Final kinetic energy KE_F=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (44.18\times 10^4)^2

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