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natima [27]
3 years ago
15

You are given and irregular shaped lump of a material and determine that it has a mass of 36.0000 g. When placed in a graduated

cylinder that initially contains exactly 22 mL of water, the water level rises to 27 mL. What is the density of the unknown material?
Chemistry
1 answer:
frosja888 [35]3 years ago
5 0

<u>Answer:</u> The density of unknown material is 7.2 g/mL

<u>Explanation:</u>

We are given:

Volume of water already in the container, V_1 = 22 mL

Volume of water rise in the cylinder, V = 27 mL

Volume occupied by unknown material = (V-V_1)=(27-22)mL=5mL

To calculate density of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Mass of unknown material = 36.0000 g

Volume of unknown material = 5 mL

Putting values in above equation, we get:

\text{Density of unknown material}=\frac{36.0000g}{5mL}\\\\\text{Density of unknown material}=7.2g/mL

Hence, the density of unknown material is 7.2 g/mL

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<h3>Further explanation</h3>

Reaction

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

mol HCOOH =

\tt 20~ml\times 0.2~M=4~mlmol

mol NaOH =

\tt 25~ml\times 0.2~M=5~mlmol

Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]

ICE method :

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

4                          5

4                          4                     4                   4

0                          1                      1                    1

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