Answer:
they repel
Explanation:
because like charges repel
Answer:
seven electrons
Explanation:
Chlorine is present in group seventeen of periodic table. It is halogen element. All halogens have seven electrons in outer most valance shell.
The require only one electron to gain the stable electronic configuration or to complete the octet.
Electronic configuration of chlorine:
Cl₁₇ = 1s² 2s² 2p⁶ 3s² 3p⁵
Abbreviated electronic configuration:
Cl₁₇ = [Ne] 3s² 3p⁵
Properties of chlorine:
1. it is greenish-yellow irritating gas.
2. its melting point is 172.2 K
3. its boiling point is 238.6 K
4. it is disinfectant and can kill the bacteria.
5. it is also used in manufacturing of paper, paints and textile industries.
B: The total thermal energy is greater in a large body of water than one much smaller
Explanation:
A large lake filled filled with cool water will have more thermal energy than smaller pond filled with warmer water because the total thermal energy is greater in a large body of water than one that is much smaller.
Thermal energy is a form of kinetic energy usually due to transfer of heat energy.
Amount of heat energy is dependent on the differences in temperature, mass and specific heat capacity of a body.
Both lake water will have the same specific heat capacity. Since larger body of water has more mass, it will possess more thermal energy.
learn more:
Specific heat capacity brainly.com/question/7210400
Thermal energy brainly.com/question/914750
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Answer:
See explaination
Explanation:
1)
we know that
half cell with higher reduction potential is cathode
so
cathode :
N20 + 2H+ + 2e- ---> N2 + H20
anode :
Cr(s) ---> Cr+3 + 3e-
so
overall reaction is
3 N20 + 6H+ + 2 Cr ---> 3N2 + 3H20 + 2Cr+3
now
Eo cell = Eo cathode - Eo anode
so
EO cell = 1.77 + 0.74
Eo cell = 2.51 V
now
in this case
oxidizing agents are N20 and Cr+3
reducing agents are Cr and N2
higher the reduction potential , stronger the oxidizing agent
lower the reduction potential , stronger the reducing agent
so
oxidzing agents
N20 > Cr+3
reducing agents
Cr > N2
2)
cathode :
Au+ + e- --> Au
anode :
Cr ---> Cr+3 + 3e-
overall reaction
3Au+ + Cr ---> 3Au + Cr+3
Eo cell = 1.69 + 0.74
Eo cell = 2.43
now
oxidizing agents :
Au+ > Cr+3
reducing agents :
Cr > Au
3)
cathode :
N20 + 2H+ + 2e- ---> N2 + H20
andoe :
Au ---> Au+ + e-
overall
2 Au + N20 + 2H+ --> 2 Au+ + N2 + H20
Eo cell = 1.77 - 1.69
Eo cell = 0.08
oxidizing agents
N20 > Au+
reducing agents
Au > N2
Answer:
Explanation:
48.16%
Well, both abundances have to total 100% so is Ag-107 is 51.84%, then Ag-109 must be 100 – 51.84 = 48.16%.
Hope This Helps :)