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natima [27]
3 years ago
15

You are given and irregular shaped lump of a material and determine that it has a mass of 36.0000 g. When placed in a graduated

cylinder that initially contains exactly 22 mL of water, the water level rises to 27 mL. What is the density of the unknown material?
Chemistry
1 answer:
frosja888 [35]3 years ago
5 0

<u>Answer:</u> The density of unknown material is 7.2 g/mL

<u>Explanation:</u>

We are given:

Volume of water already in the container, V_1 = 22 mL

Volume of water rise in the cylinder, V = 27 mL

Volume occupied by unknown material = (V-V_1)=(27-22)mL=5mL

To calculate density of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Mass of unknown material = 36.0000 g

Volume of unknown material = 5 mL

Putting values in above equation, we get:

\text{Density of unknown material}=\frac{36.0000g}{5mL}\\\\\text{Density of unknown material}=7.2g/mL

Hence, the density of unknown material is 7.2 g/mL

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10. A small helium tank claims to be able to fill 30 balloons to a volume of 3.15 L
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Taking into account the Boyle's law, 3.377 L of helium the tank will be able to  produce at a pressure of 94.2 kPa.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature, and moles.

Boyle's law is one of the gas laws that relates the volume and pressure of a certain quantity of gas kept at constant temperature.

This law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases; while if the pressure decreases, the volume increases.

Mathematically, Boyle's law states that the product of pressure and volume is constant:

P×V= k

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

P1× V1= P2×V2

In this case, you know:

  • P1= 101 kPa
  • V1= 3.15 L
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Replacing in Boyle's law:

101 kPa× 3.15 L= 94.2 kPa× V2

Solving:

V2=\frac{101 kPa x3.15 L}{94.2 kPa}

<u><em>V2= 3.377 L</em></u>

In summary, 3.377 L of helium the tank will be able to  produce at a pressure of 94.2 kPa.

Learn more:

brainly.com/question/4147359?referrer=searchResults

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Answer:

Concentration of solution B is 7.10\times 10^{-6}M

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where C_{1} and C_{2} are initial and final concentration respectively. V_{1} and V_{2} are initial and final volume respectively.

Here C_{1} = 3.55\times 10^{-4}M, V_{1} = 1.00 mL, V_{2} = 10.00 mL

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So, concentration of solution A = 3.55\times 10^{-5}M

Solution B: Total volume of solution B = (2.00+8.00) mL = 10.00 mL

Similarly as above, C_{2}=\frac{C_{1}V_{1}}{V_{2}} = \frac{3.55\times 10^{-5}M\times 2.00mL}{10.00mL}=7.10\times 10^{-6}M

So, concentration of solution B = 7.10\times 10^{-6}M

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