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4 years ago

A single replacement reaction is a reaction in which one element replaces a similar element within a compound. True or false?

Chemistry

1 answer:

AleksAgata [21]4 years ago

8 0

Answer:

true

Explanation:

A single replacement reaction is a reaction that an element is displaced with another element in a compound

A+BC------AC+B

Mg+2HCl-------MgCl2+H2

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Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol)

kolbaska11 [484]

Answer:

The amount of NaOH required to prepare a solution of 2.5N NaOH.

The molecular mass of NaOH is 40.0g/mol.

Explanation:

Since,

NaOH has only one replaceable -OH group.

So, its acidity is one.

Hence,

The molecular mass of NaOH =its equivalent mass

Normality formula can be written as: $Normality=\frac{mass of solute NaOH}{its equivalent mass} * \frac{1}{volume of solution in L} \\$

Substitute the given values in this formula to get the mass of NaOH required.

$2.5N=\frac{mass of NaOH}{40g/mol} *\frac{1}{1L} \\mass of NaOH=2.5N*40gmol\\ = 100.0g$

Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g

8 0

3 years ago

What is S for the reaction N2(g) +O2(g) 2NO? Use G = 173.3 kJ at 303.0 K and H = 180.7 kJ. Use G = H – TS.

Rashid [163]

Given information :

G = 173.3 KJ

H = 180.7 KJ

T = 303.0 K

S = unknown (?)

By using the given formula : G = H - TS , we can calculate the value of 'S'

On rearranging the formula we get : S = $\frac{H-G}{T}$

Plug in the value of G , H and T in the above formula :

S = $\frac{(180.7 KJ - 173.3KJ)}{303.0K}$

S = 0.02442 $\frac{KJ}{K}$

4 0

3 years ago

Read 2 more answers

A student isolated 25 g of a compound following a procedure that would theoratically yield 81 g. Wht was his percentt yield?

Sati [7]

<u>Answer:</u> The percent yield of the compound is 30.86 %.

<u>Explanation:</u>

To calculate the percentage yield of a compound, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of compound = 25 g

Theoretical yield of compound = 81 g

Putting values in above equation, we get:

$\%\text{ yield of compound}=\frac{25g}{81g}\times 100\\\\\% \text{yield of compound}=30.86\%$

Hence, the percent yield of the compound is 30.86 %.

3 0

4 years ago

You have plenty of salts that are in front of you and you are trying to figure out which salts are soluble in water, and which o

slamgirl [31]

Given NH4Cl + NaClO3 =

In order to figure out which salts are soluble in water, and which ones of their products are soluble in water:

we will have the following Molecular products :

• NH4Cl + NaClO3 = NaCl + NH4ClO3,

( both salts are soluble in water)

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1 year ago

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What is the molar mass of sand (SiO2) to the hundredths place in g/mol?

ad-work [718]

Answer:

60.08g/mol

Explanation:

Given parameters:

Formula of sand = SiO₂

Find the molar mass of the compound to the hundredths place;

Molar mass of Si = 28.085g/mol

Molar mass of O = 15.999

Molar mass = 28.085 + 2(15.999) = 60.08g/mol

4 0

3 years ago