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jekas [21]
3 years ago
5

An arithmetic sequence is defined by the recursive formula t1 = 11, tn = tn - 1 - 13, where n ∈N and n > 1. Which of these is

the general term of the sequence?
Mathematics
1 answer:
galben [10]3 years ago
6 0

coolio

t_1=11

t_n=t_{n-1}-13

so each term is ound by subtracting 13 from the previous term


an aritmetic sequence can be written as

t_n=t_1+d(n-1) were

t_n is the nth term

t_1 is the first term

d is common difference, which can also be found by doing t_n-t_{n-1}=d

n=wich term


we know that t_1=11 and we can find d

t_n=t_{n-1}-13, t_n-t_{n-1}=-13=d

so te general term is t_n=11-13(n-1) which can also be expanded and written as t_n=-13n+24

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trapecia [35]

Answer:

i believe the relative max coordinate is (2,4)

relative min is (-2,0) and (4,0)

and these are not absolute exterma maybe because there are more than one relative min?

6 0
2 years ago
3. Michel invests $850 at 7%/a simple interest. How long will he
Kipish [7]

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&\$200\\ P=\textit{original amount deposited}\dotfill & \$850\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ t=years \end{cases} \\\\\\ 200=850(0.07)t\implies \cfrac{200}{850(0.07)}=t\implies \stackrel{\textit{about 3 years, 4 months and 10 days}}{3.36\approx t}

5 0
2 years ago
An empty bucket weighs 800g.
erica [24]

Answer:

412.5 percent

7 0
3 years ago
Read 2 more answers
Can someone please help me with this :(
mrs_skeptik [129]

Answer:

first find the surface area of one of the square and one of the triangle.

then multiple it by the number of square and triangle they have

finally add the total surface area of the triangle with the total surface area of the square.

Step-by-step explanation:

  1. for one square

area= base * width

= 10*10

=100

total area of square= number of square * area of one square

t=6*100

t=600

  • for one triangle

area = 1/2 base * height

= 1/2 *10*8.66

=43.3

total area of triangle=number of triangle* area of one triangle

t2=8*43.3

=346.4

total surface area= total surface area of the square+ total surface area of the triangle

=600+346.4

=946.4 in^2

5 0
2 years ago
HELP PRECALC DO NOT UNDERSTAND WILL GIVE BRAINLIEST
Olegator [25]

Answer:

  the lower right matrix is the third correct choice

Step-by-step explanation:

Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).

Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.

__

We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.

The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...

  \left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]

Already, we see that the second row matches that in the lower right matrix.

The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.

The correct choices here are the two you have selected, and <em>the lower right matrix</em>.

3 0
3 years ago
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