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shtirl [24]
3 years ago
15

Calculate the magnitude of q for a system that does 603000 kJ of work on its surroundings and for which the change in total inte

rnal energy is −1.80 × 104 kJ.
Physics
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

Q=585000 kJ

Explanation:

Given Data

W (Work)=603000 kJ

ΔU (Change in total internal energy)=-1.80×10⁴ kJ

Q (Heat Supplied)=?

Solution

First Law of thermodynamic:

The first law of thermodynamics states that energy can neither be created nor destroyed, but only converted between various forms. For a closed system, we may write the change in internal energy as:  

ΔU=Q-W

Q=ΔU+W

Q= -1.80×10⁴+603000

Q= 585000 kJ

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