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mixas84 [53]
4 years ago
11

What are the factors of diffusion?

Chemistry
2 answers:
sladkih [1.3K]4 years ago
8 0
Several factors<span> affect the rate of diffusion of a solute including the mass of the solute, the </span>temperature<span> of the environment, the solvent </span>density, and thedistance<span> traveled.</span>
GarryVolchara [31]4 years ago
3 0
Well, I just know only a few factors of it. 1. Size of the particle 2. Temperature 3. Concentration Difference 4. Permeability Hope I helped c:
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Which of the following reactions would result in decreased entropy? (multiple choice)
jasenka [17]

Answer:

D

Explanation:

Since the state of matter is going from a gas to a solid, it would be going from a state of high entropy (greater disorder) to a state of lower entropy (less disorder).

8 0
3 years ago
Please help me with these?
Julli [10]

Question 5 is the second one.


8 0
3 years ago
I WILL GIVE BRAINLIEST!!!!
lions [1.4K]

The correct answer is option c, that is, nucleus.  

A usual atom comprises three subatomic particles, that is, the neutrons, protons, and electrons. According to Bohr's model, the majority of the mass of an atom is in the nucleus, that is, a small, dense region at the center of each atom, comprising nucleons.  

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3 0
4 years ago
The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.13 M, it takes ________ min for
Zigmanuir [339]

Answer:

Therefore it takes 8.0 mins for it to decrease to 0.085 M

Explanation:

First order reaction: The rate of reaction is proportional to the concentration of reactant of power one is called first order reaction.

A→ product

Let the concentration of A = [A]

\textrm{rate of reaction}=-\frac{d[A]}{dt} =k[A]

k=\frac{2.303}{t} log\frac{[A_0]}{[A]}

[A₀] = initial concentration

[A]= final concentration

t= time

k= rate constant

Half life: Half life is time to reduce the concentration of reactant of its half.

t_{\frac{1}{2} }=\frac{0.693}{k}

Here t_{\frac{1}{2} }=0.13 min

k=\frac{0.693}{t_{\frac{1}{2}} }

\Rightarrow k=\frac{0.693}{13 }

To find the time takes for it to decrease to 0.085 we use the below equation

k=\frac{2.303}{t} log\frac{[A_0]}{[A]}

\Rightarrow t=\frac{2.303}{k} log\frac{[A_0]}{[A]}

Here ,   k=\frac{0.693}{13 },  [A₀] = 0.13 m and [ A] = 0.085 M

t=\frac{2.303}{\frac{0.693}{13} } log(\frac{0.13}{0.085})

\Rightarrow t= 7.97\approx 8.0

Therefore it takes 8.0 mins for it to decrease to 0.085 M

7 0
3 years ago
Three friends were kicking soccer balls at a neighborhood field. Three soccer balls were rolling across the field. The black soc
BARSIC [14]

Answer: d :The blue and orange soccer balls; they have more mass than the black soccer ball, but changed speed by the same amount.

3 0
3 years ago
Read 2 more answers
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