Question

1.

Answer 1

Answer:

1.No of moles of SO2=6.022*10^24/AVAGARDOS NUMBER

No of moles=10

1 Moles of So2 contains 1 moles of s and 2 moles of o

10 mole of so2 contains 10 moles of s and 20 moles of o

No of moles of o=weight in gram of o/atomic weight

20*16=Weight =320 kg

And similarly for sulphur(atomic weight32)

2.1.5055x10^23 C atoms and 6.022x10^23 H atoms

=>

Molar Mass of 1 molecule of methane(CH4) = 12 +

4 = 16g/mol =

That is, 16g if CH4 contain 1 mole molecule of it

= 6.022x1023 molecules of CH4 which consists of 1 mole of C atoms and 4 moles of H atoms.

=> 4 g of CH4 contains 1/4 x 6.022x1023

molecules

= 1.5055*10^23 molecules of CH4

= 1.5055*10^23 C atoms and 6.022x10^23 H atoms

Answer 2

Answer:

1 mol SO2 contains 6.0213*10^23 molecules

6.023*10^24 molecules = 10 mol SO2

Equation

S(s) + O2(g) → SO2(g)

1 mol S reacts with 1 mol O2 to prepare 1 mol SO2

To prepare 10 mol SO2 you require : 10 mol S plus 10 mol O2

And that is the answer to the question

If you want a mass :

Molar mass S = 32 g/mol You require 10 mol = 320 g

Molar mass O2 = 32 g/mol :You require 10 mol = 320 g