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3 years ago

What's the difference between asexual reproduction and sexual reproduction?!?!

2 answers:

8 0

Hello!

This is simple, asexual reproduction involves only one parent, and does not need to involve the <span>fusion of gametes. On the other hand, Sexual reproduction involves two parents and does need to fuse together different gametes and needs the genes from both sexes of the plants.

I hope this helped!

I am, yours most sincerely,
SuperHelperThingy</span>

Leni [432]3 years ago

5 0

Sexual reproduction is the combination between the genetic material of both two parents while asexual reproduction produces offspring genetically identical to the one parent. Also, asexual reproduction produces without sex while sexual reproduction requires it. These are the most common differences between the two reproduction processes.

I hope this helps!<span />

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A 0.48 kg pool cue moving at 3.39 m/s hits the 0.22 kg cue ball that was a rest and the pool cue stops after the impact. What is

Grace [21]

Answer:

7.39 m/s is the velocity of the cue ball after impact.

Explanation:

Given that,

$\text { Mass of the pool cue is } 0.48 \mathrm{kg} .\left(\mathrm{m}_{\mathrm{i}}\right)$

$\text { Moving at velocity } 3.39 \mathrm{m} / \mathrm{s} .(\mathrm{v_i})$

$\text { Mass of the cue ball that } 0.48 \text { mass ball hits is } 0.22 \mathrm{kg} .\left(\mathrm{m}_{\mathrm{f}}\right)$

$\text { We need to find the velocity ( } \mathrm{v}_{\mathrm{f}} \text { ) of the cue ball of mass } 0.22 \mathrm{kg} \text { . }$

We know that,

If two objects collide then the “total momentum” before is equal to the “total momentum” after collision.

$\mathrm{m}_{\mathrm{i}} \mathrm{v}_{\mathrm{i}}=\mathrm{m}_{\mathrm{f}} \mathrm{V}_{\mathrm{f}}$

Substitute the given values in the formula.

$0.48 \times 3.39=0.22 \times \mathrm{V}_{\mathrm{f}}$

$\frac{1.6272}{0.22}=\mathrm{V}_{\mathrm{f}}$

$\mathrm{v}_{\mathrm{f}}=7.39 \mathrm{m} / \mathrm{s}$

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4 years ago

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3 years ago

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Answer:

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A speed truck locks it’s brakes and it skids to a stop. If the truck’s total mass were doubled, it’s skidding distance would be?

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Answer:

The skidding distance would be doubled

Explanation:

When the truck applies the brakes and slows down, its motion is a uniformly accelerated motion, so its skidding distance can be found by using the suvat equation

$v^2-u^2=2as$

where

v = 0 is the final velocity (zero since the truck comes to a stop)

u is the initial velocity

a is the acceleration

s is the skidding distance

The acceleration can also be written as

$a=\frac{F}{m}$

where F is the force applied by the brakes and m the mass of the truck. Substituting into the previous equation,

$-u^2 = 2\frac{F}{m}s\\s = -\frac{mu^2}{2F}$

We see that the skidding distance is proportional to the mass: therefore, if the mass of the truck is doubled, the skidding distance will double as well.

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