Answer:
Chemical reactions that take place inside living things are called biochemical reactions. The sum of all the biochemical reactions in an organism is called metabolism. Metabolism includes both exothermic (energy-releasing) chemical reactions and endothermic (energy-absorbing) chemical reactions.
Explanation:
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Solution :
Cd(s) ----------------------> 
(aq) + 2
, 
= 0.34 v
(aq) + 2 ------------> Cu (s) , = -0.04 v
----------------------------------------------------------------------------------------------
Cd(s) + (aq) -------------> (aq) + Cu (s) , = 0.30 v
The cell potential is defined as the measure of 
between the 
of an electrochemical cell.
A-Locations M and O are at the poles.
Explanation:
Locations M and O are located at the poles because they receive sunlight that is spread out over a large surface area. The poles receive sunlight at an angle to the surface and it causes the rays of the sun to spread out in all direction.
- At the equator, sunlight impinges directly on the surface and the solar radiation here is very much.
- It is important to know that the sun is overhead directly at the equator.
- The earth is tilted at an angle to sun and therefore, areas around the polar region will receive sunlight that is spread out in different directions over a large area.
- Away from the pole, the equator is directly facing the sun and it receives direct sunlight.
Learn more:
solar radiation brainly.com/question/10940063
#learnwithBrainly
Answer:
In the third tube, the concentration is 0.16 ug/mL
Explanation:
In the first step, the solution is diluted by 5. Then, the concentration will be
20 ug/mL / 5 = 4 ug/mL
Then, in the second step this 4 ug / ml solution is diluted by a factor of five again:
4 ug /ml / 5 = 0.8 ug/mL
This solution is then diluted again by 5 and the concentration in the third tube will be then:
0.8 ug/mL / 5 = <u>0.16 ug/mL </u>
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Another way to calculate this is to divide the original concentration by the dilution factor ( 5 in this case) elevated to the number of dilutions. In this case:
Concentration in the third tube = 20 ug/mL / 5³ = 0.16 ug/mL
