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sesenic [268]
3 years ago
7

the frequency of green light is 6×101^4 what is it's wavelengththe frequency of green light is 6 x 10 raise to power 14 what is

its wavelength ​
Physics
1 answer:
vladimir1956 [14]3 years ago
5 0

Answer:

5×10^-7m

Explanation:

Known/Given:

speed of light, c = 3.00 x 10^8 m/s

frequency, ν = 6 x 10^14 Hz

Equation:

c = λν

Solution:

To solve for wavelength,

λ, rearrange the equation so that

λ = c/ν.

λ = (3.00 x 10^8m/s)/(6 x 10^14/s) = 5×10^−7m

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A hydrogen atom contains a single electron that moves in a circular orbit about a single proton. Assume the proton is stationary
riadik2000 [5.3K]

Answer:

Radius between electron and proton= 6.804\times 10^{-10}m

Explanation:

The motion of the electron is carried out in the orbit due to the balancing of the electrostatic force between the proton and the electron and the centripetal force acting on the electron.

The electrostatic force is given as = \frac{kq_1q_2}{r^2}

Where,

k = coulomb's law constant (9×10⁹ N-m²/C²)

q₁ and q₂  = charges = 1.6 × 10⁻¹⁹ C

r = radius between the proton and the electron

Also,

Centripetal force on the moving electron is given as:

=\frac{m_eV^2}{r}

where,

m_e = mass of the electron (9.1 ×10⁻³¹ kg)

V = velocity of the moving electron (given: 6.1 ×10⁵ m/s)

Now equating both the formulas, we have

\frac{kq_1q_2}{r^2} = \frac{m_eV^2}{r}

⇒r = \frac{kq_1q_2}{m_eV^2}

substituting the values in the above equation we get,

r = \frac{9\times 10^{9}\times (1.6\times 10^{-19})^2}{9.1\times 10^{-31}\times (6.1\times 10^5)^2}

⇒r = 6.804\times 10^{-10}m

3 0
3 years ago
Calculate the kinetic energy in joules of a 1500 kg automobile moving at 17 m/s . express your answer to two significant figures
Sidana [21]
Kinetic energy = 1/2 (mass)*(velocity)^2

ke = 1/2 (1500kg) (17m/s)^2
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(sorry, I don't know significant figures. but this is otherwise the correct answer with the right units. hope this helps!! :))
6 0
4 years ago
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