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sesenic [268]
3 years ago
7

the frequency of green light is 6×101^4 what is it's wavelengththe frequency of green light is 6 x 10 raise to power 14 what is

its wavelength ​
Physics
1 answer:
vladimir1956 [14]3 years ago
5 0

Answer:

5×10^-7m

Explanation:

Known/Given:

speed of light, c = 3.00 x 10^8 m/s

frequency, ν = 6 x 10^14 Hz

Equation:

c = λν

Solution:

To solve for wavelength,

λ, rearrange the equation so that

λ = c/ν.

λ = (3.00 x 10^8m/s)/(6 x 10^14/s) = 5×10^−7m

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What is the wavelength of a wave with a frequency of 200Hz while traveling at 125.5m/s
nikdorinn [45]

Answer:

0.6275 metres

Explanation:

v = fl

125.5 = 200 * wavelength

125.5 / 200 = wavelength = 0.6275m

4 0
3 years ago
Which statement best describes how the temperature of the oceans surface water varies
lorasvet [3.4K]
If the temperature is high there is less water because it evaporates if it is cloudy it is more because it doesn't evaporate
8 0
3 years ago
NASA is designing a Mars-lander that will enter the Martian atmosphere at high speed. To land safely it must slow to a constant
Viktor [21]

Answer:

a) maximum mass of the Mars lander to ensure it can land safely is 200 kg

b) area of the parachute required is 480 m² which is larger than 400 m²

c) area of the parachute should be 12.68 m²

Explanation:

Given the data in the question;

V = 20 m/s

A = 200 m²

drag co-efficient CD = 1.855

g = 3.71 m/s²

density of the atmospheric pressure β = 0.01 kg/m³

a. Calculate the maximum mass of the Mars lander to ensure it can land safely?

Drag force FD = 1/2 × CD × β × A × V²

we substitute

FD = 1/2 × 1.855 × 0.01 kg/m × 200 m² × ( 20 m/s )²

FD = 742 N

we know that;

FD = Fg

Fg = gravity force

Fg = mg

so

FD = mg

m = FD/g

we substitute

m = 742 N / 3.71 m/s²

m = 200 kg

Therefore, the maximum mass of the Mars lander to ensure it can land safely is 200 kg

b. The mission designers consider a larger lander with a mass of 480 kg. Show that the parachute required would be larger than 400 m²;

Given that;

M = 480 kg

Show that the parachute required would be larger than 400 m²

we know that;

FD = Fg = Mg = 480 kg × 3.71 m/s²

FD = 1780.8 N

Now, FD = 1/2 × CD × β × A × V², we solve for A

A = FD / 0.5 × CD × β × V²

we substitute

A = 1780.8  / 0.5 × 1.855 × 0.1 × (20)²

A = 1780.8 / 3.71

A = 480 m²

Therefore, area of the parachute required 480 m² which is larger than 400 m²

c. To test the lander before launching it to Mars, it is tested on Earth where g = 9.8 m/s^2 and the atmospheric density is 1.0 kg m-3. How big should the parachute be for the terminal speed to be 20 m/s, if the mass of the lander is 480 kg?

Given that;

g = 9.8 m/s²,

β" = 1 kg/m³

v" = 20 m/s

M" = 480 kg

we know that;

FD = Fg = M"g

FD = 480 kg × 9.8 m/s² = 4704 N

from the expression; FD = 1/2 × CD × β × A × V²

A = FD / 0.5 × CD × β" × V"²

we substitute

A = 4704 / 0.5 × 1.855 × 1 × (20)²

A = 4704 / 371

A = 12.68 m²

Therefore area of the parachute should be 12.68 m²

3 0
3 years ago
One event occurs at the origin at t equal to zero, and a second events occurs at the point x=5m along the x-axis at time with ct
Anastasy [175]

Answer:

  • The separation will be spacelike.
  • The first event can't cause the second event, as there exist an frame of reference in which both happens at the same time, in different positions, so, if there were causally connected, it will imply an instant connection, this is faster than light.

Explanation:

We can define the separation between two events (using the + - - - signature)  as :

(\Delta s )^2  = (ct_2 - c t_1 )^2 - (x_2 - x_1)^2

where the separation will be lightlike if is equal to zero, timelike if is positive and spacelike if is negative.

For our problem

c t_1 = 0

x_1 = 0

ct_2 = 4 \ m

x_2 = 5 \ m

(\Delta s )^2  = (4 \ m - 0 )^2 - ( 5 \ m - 0)^2

(\Delta s )^2  = (4 \ m )^2 - ( 5 \ m 0)^2

(\Delta s )^2  = 16 \ m^ 2 - 25 \ m^2

(\Delta s )^2  = - 9\ m^2

So the separation will be spacelike, and the first event can't cause the second event, as there exist an frame of reference in which both happens at the same time, in different positions, so, if there were causally connected, it will imply an instant connection, this is faster than light.

8 0
4 years ago
A sound can be ________ or _________.
marin [14]
A.
Sorry if it’s wrong
3 0
3 years ago
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