If you remember the formula for potential energy,
then this question is a piece-o-cake.
<em>Potential energy = (mass) x (<u>acceleration of gravity</u>) x (height) .</em>
-- The object's mass is the same everywhere.
-- You said that the height is the same both times.
-- How about the acceleration of gravity ?
Compared to gravity on Earth, it's only 16.5 percent as much on the Moon.
So naturally, from the formula, you'd expect the Potential Energy to be less
on the Moon.
Answer
given,
diameter of the pipe is = (14 ft)4.27 m
minimum speed of the skater must have at very top = ?
At the topmost point of the pipe the normal force will be equal to zero.
F = mg
centripetal force acting on the skateboard
![F = \dfrac{mv^2}{r}](https://tex.z-dn.net/?f=F%20%3D%20%5Cdfrac%7Bmv%5E2%7D%7Br%7D)
equating both the force equation
![mg = \dfrac{mv^2}{r}](https://tex.z-dn.net/?f=mg%20%3D%20%5Cdfrac%7Bmv%5E2%7D%7Br%7D)
![v = \sqrt{gr}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7Bgr%7D)
r = d/2 = 14/ 2 = 7 ft
or
r = 4.27/2 = 2.135 m
g = 32 ft/s² or g = 9.8 m/s²
![v = \sqrt{32 \times 7}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B32%20%5Ctimes%207%7D)
v = 14.96 ft/s
or
![v = \sqrt{9.8 \times 2.135}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B9.8%20%5Ctimes%202.135%7D)
v = 4.57 m/s
Answer:
Explanation:
To stop a ball with high momentum in a small-time imparts a high amount of impact on hands. This is the reason for the stinging of hands.
The momentum of the ball is due to the mass and velocity. To prevent stinging in the hand one needs to lower his hands to increase the time of contact. In this way, the momentum transfer to the hands will be lesser.
Answer:
Reduce the friction at the surface
Explanation:
If you can reduce the friction between the load and the plane less effort will be required as you are not having to apply effort to overcome friction.