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tatyana61 [14]
3 years ago
5

Thirty five soccer players were challenged to do as many sit-ups possible in two minutes

Physics
1 answer:
Ghella [55]3 years ago
7 0

Answer:

Explanation:

What is the question?

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A student initially 10.0 m East of his school walks 17.5 m West. The magnitude of the student's displacement, relative to the sc
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A horizontal force of 92.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.13 m/s2, wha
lord [1]

Answer:

The value is F_f =  46.935 \  N

Explanation:

From the question we are told that

    The  magnitude of the horizontal force is F  =  92.7 \  N

     The mass of the crate is  m  =  40.5 \  kg

     The acceleration of the crate is  a =  1.13 \ m/s

Generally the net force acting on the crate is mathematically represented as

       F_{net} =  F -  F_f =  ma

Here F_f is force of kinetic friction (in N) acting on the crate

      So  

            92.7  -  F_f =  40.5 * 1.13

=>         F_f =  46.935 \  N

5 0
3 years ago
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