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tatyana61 [14]
2 years ago
5

Thirty five soccer players were challenged to do as many sit-ups possible in two minutes

Physics
1 answer:
Ghella [55]2 years ago
7 0

Answer:

Explanation:

What is the question?

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3. Which of the following is the correctly abbreviated SI unit describing the mass of an object?
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Your answer will be A) KILOGRAMS
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If the pressing force on the slidding surfaces is greater then friction will be
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Answer:

Kinetic friction is lesser than limiting friction. Two surfaces are rubbed together, first with a smaller force and then with a greater force.

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2 years ago
A 5cm tall object is placed 4cm in front of a converging lens that has a focal length of 8cm. Where is the image located in ____
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Answer:

a. -8 cm

Explanation:

d_{o} = distance of the object = 4 cm

d_{i} = distance of the image = ?

f = focal length of the converging lens  = 8 cm

using the lens equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{4} + \frac{1}{d_{i}} = \frac{1}{8}

d_{i} = - 8 cm

4 0
2 years ago
Briefly explain the difference between being self-centered and
tensa zangetsu [6.8K]

Answer:

Explanation:

Self centered means you think about yourself and can sometimes mean that you're arrogant. Self aware means you are aware of certain things you do. Self centered has a negative connotation while self aware has a positive one.

6 0
3 years ago
Read 2 more answers
In an Atwood's machine, one block has a mass of 602.0 g, and the other a mass of 717.0 g. The pulley, which is mounted in horizo
Wittaler [7]

Answer:

The acceleration of the both masses is 0.0244 m/s².

Explanation:

Given that,

Mass of one block = 602.0 g

Mass of other block = 717.0 g

Radius = 1.70 cm

Height = 60.6 cm

Time = 7.00 s

Suppose we find  the magnitude of the acceleration of the 602.0-g block

We need to calculate the acceleration

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Where, s = distance

t = time

a = acceleration

Put the value into the formula

60.0\times10^{-2}=0+\dfrac{1}{2}\times a\times(7.00)^2

a=\dfrac{60.0\times10^{-2}\times2}{(7.00)^2}

a=0.0244\ m/s^2

Hence, The acceleration of the both masses is 0.0244 m/s².

5 0
3 years ago
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