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kykrilka [37]
1 year ago
5

What observational evidence suggests that supermassive black holes are located at the centers of many galaxies

Physics
1 answer:
RoseWind [281]1 year ago
5 0

Observational evidence suggests that supermassive black holes are located at the centers of many galaxies is rapid & sudden changes in the orbits of stars & other objects in the galactic center.

<h3>What are black holes?</h3>

A black hole is an area of spacetime with such intense gravitational pull that nothing can escape from it, not even light or other electromagnetic waves. According to general relativity theory, a compact enough mass can bend spacetime into a black hole. The event horizon is the line beyond which there is no escape. Despite having a significant impact on the outcome and circumstances of an object traversing it, general relativity states that it lacks any locally observable characteristics. A black hole behaves in many ways like a perfect black body since it does not reflect light.

To learn more about black holes visit:

brainly.com/question/10597324

#SPJ4

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Explain the energy transfer if a book on the edge of a table, falls to the floor. There should be 3 types of energy transfers.
gavmur [86]

Answer:

potential energy

kinetic energy

thermal energy

Explanation:

The book's potential energy can be released by knocking it off the table. As the book falls, its potential energy is converted to kinetic energy. When the book hits the floor this kinetic energy is converted into heat and sound by the impact.

6 0
3 years ago
Read 2 more answers
A quantum system has three states, with energies 0, 1.6 × 10-21, and 1.6 × 10-21, in Joules. It is coupled to an environment wit
xenn [34]

To develop the problem it is necessary to apply two concepts, the first is related to the calculation of average data and the second is the Boltzmann distribution.

Boltzmann distribution is a probability distribution or probability measure that gives the probability that a system will be in a certain state as a function of that state's energy and the temperature of the system. It is given by

z = \sum\limit_i e^{-\frac{\epsilon_i}{K_0T}}

Where,

\epsilon_i = energy of that state

k = Boltzmann's constant

T = Temperature

With our values we have that

T= 250K

k = 1.381*10^{23} m^2 kg s^{-2} K^{-1}

\epsilon_1=0J

\epsilon_2=1.6*10^{-21}J

\epsilon_3=1.6*10^{-21}J

To make the calculations easier we can assume that the temperature and Boltzmann constant can be summarized as

\beta = \frac{1}{kT}

\beta = \frac{1}{(1.381*10^{23} m^2)(250)}

\beta = 2.9*10^{20}J

Therefore the average energy would be,

\bar{\epsilon} =\frac{\sum \epsilon_i e^{-\beta \epsilon_i}}{\sum e^{-\beta \epsilon_i}}

Replacing with our values we have

\bar{\epsilon} = \frac{0e^{-0}+1.6*10^{-21}*e^{-\Beta(1.6*10^{-21})}+1.6*10^{-2-1}*e^{-(2.9*10^{20})(1.6*10^{-21})}}{1+2e^{-2.9*10^{20}*1.6*10^{-21}}}

\bar{\epsilon} = 0.9*10^{-22}J

Therefore the average internal energy is \bar{\epsilon} = 0.9*10^{-22}J

3 0
3 years ago
Which of the following tools is used to mark the spot where a hole is to be drilled in a piece of metal?
Oxana [17]
That's a job for a center-punch.
3 0
4 years ago
Read 2 more answers
Describe and explain how energy is transferred in the bulbs. Use scientific ideas to support your answer
Lelechka [254]

Answer:

In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy.

Explanation:

In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy.

6 0
2 years ago
A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of
nlexa [21]

Answer:

The change in momentum is  \Delta p =   0.7 \ kg\cdot m \cdot s^{-1}

Explanation:

From the question we are told that

    The time taken for the stone to stop is \Delta  t = 0.15 \ seconds

    The net force on the rock is  F =  58 \ N

   

The impulse of the rock can be mathematically represented as

     I  =  F * \Delta t

Substituting values

     I  =  58 * 0.15

    I  =  0.7\  kg * m  * s^{-1}

Now impulse is defined as  the rate at which momentum change

   Hence the change in momentum \Delta p  of the rock is equal to the impulse of the rock

 So  

       \Delta p =  I  =  0.7 \ kg\cdot m \cdot s^{-1}

7 0
4 years ago
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