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victus00 [196]
3 years ago
7

The temperature of a substance during an experiment can be modeled by the function f(x)=−7.5cos(πx30)+31.4 , where f(x) is the t

emperature °c and x is the number of minutes into the experiment. what is the greatest temperature the substance reached during the experiment?
Physics
2 answers:
vekshin13 years ago
6 0
38.9 degrees celsius
ololo11 [35]3 years ago
6 0

Answer :  f(x)=38.9^0\ C

Explanation :

It is given that,

The temperature of a substance during an experiment is given by a function as :

f(x)=-7.5cos(\dfrac{\pi x}{30})+31.4................(1)

Where,

f(x) is the temperature

and x is the time.

So, for getting a maximum temperature the substance reached during the experiment the value of cos( \dfrac{\pi x}{30}) should by minimum.

We know that the value of cos is minimum at \pi.

So, cos( \dfrac{\pi x}{30})=cos\pi

We get, x = 30

Put the value of x in equation (1)

f(x) = -7.5cos(\dfrac{\pi \times 30}{30})+31.4

Since, cos \pi=-1

f(x)=38.9^0\ C

So, the greatest value of temperature the substance reached during the experiment is f(x)=38.9^0\ C.

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A weightlifter completes a series of lifts with a 700 N weight. In one lift, he raises the weight to a height of 2.5 m off the g
zhannawk [14.2K]

Answer:

The output power the weightlifter is 2916.67 W.

Explanation:

Given;

weight lifted, W = 700 N

height the weight is lifted, h = 2.5 m

time taken to lift the weight, t = 0.60 s

The output power the weightlifter is calculated as;

Power = Energy applied / time taken

Energy applied = weight lifted x height the weight is lifted

Energy applied = 700 x 2.5

Energy applied = 1750 J

Power = 1750 / 0.6

Power = 2916.67 J/s = 2916.67 W.

Therefore, the output power the weightlifter is 2916.67 W.

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In tae-kwon-do, a hand is slammed down onto a target at a speed of 10 m/s and comes to a stop during the 7.0 ms collision. Assum
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Answer:

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