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3 years ago

What is the velocity of a Usain Bolt if he runs 200 m in 10 seconds?

Physics

1 answer:

Yuki888 [10]3 years ago

8 0

Answer:

20m/s

Explanation:

Given parameters:

Displacement = 200m

Time = 10s

Unknown:

Velocity of Usain Bolt = ?

Solution:

The velocity of a body is the displacement divided by the time taken.

Therefore

Velocity = $\frac{displacement}{time}$

So;

Velocity = $\frac{200}{10}$ = 20m/s

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A lens of focal length 10.0 cm

fgiga [73]

Answer:

30cm

Explanation:

7 0

2 years ago

What potential difference is required to cause 4.00 a to flow through a resistance of 330 ω?

Alisiya [41]

We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
$\Delta V = I R$
where
$\Delta V$ is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance

In our problem, I=4.00 A and $R=330 \omega$ , so the potential difference is
$\Delta V = IR=(4.00 A)(330 \omega)=1320 V$

7 0

3 years ago

Describe the motion of a swing that requires 6 seconds to complete one cycle. What is its period and the frequency? Round to the

shutvik [7]

Period = 6 seconds and $frequency = 0.167Hz$ .

<u>Explanation:</u>

We have , the motion of a swing that requires 6 seconds to complete one cycle. Period is the amount of time needed to complete one oscillation . And in question it's given that 6 seconds is needed to complete one cycle. Hence ,Period of the motion of a swing is 6 seconds . Frequency is the number of vibrations produced per second and is calculated with the formula of $\frac{1}{t}$ . SI unit of frequency is Hertz or Hz. We know that time period is 6 seconds so frequency = $\frac{1}{t}$

⇒ $frequency = \frac{1}{time}$

⇒ $frequency = \frac{1}{6}$

⇒ $frequency = 0.167Hz$

Therefore , Period = 6 seconds and $frequency = 0.167Hz$ .

7 0

3 years ago

Which item is not considered electromagnetic energy?

suter [353]

Sound waves are known to be the one that's not considered as a type of electromagnetic energy. As for microwaves and x-rays, they tend to share the same frequencies that can be considered as electromagnetic, and sound waves have a different frequency than them.

5 0

3 years ago

g n diffraction, the formula for minima is given by a times s i n (theta )equals m lambda, where a is the width of the slit, the

ki77a [65]

Answer:

θ = 22.2

Explanation:

This is a diffraction exercise

a sin θ = m λ

The extension of the third zero is requested (m = 3)

They indicate the wavelength λ = 630 nm = 630 10⁻⁹ m and the width of the slit a = 5 10⁻⁶ m

sin θ = m λ / a

sin θ = 3 630 10⁻⁹ / 5 10⁻⁶

sin θ = 3.78 10⁻¹ = 0.378

θ = sin⁻¹ 0.378

to better see the result let's find the angle in radians

θ = 0.3876 rad

let's reduce to degrees

θ = 0.3876 rad (180º /π rad)

θ = 22.2º

4 0

3 years ago