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frez [133]
3 years ago
15

A cylinder contains 250 g of Helium at 200 K. The external pressure is constant at 1 atm. The temperature of the system is raise

d by 74 K. Calculate the heat lost or gained by the system. Calculate your answer to three significant figures and express you answer in J. Heat capacity for Helium = 20.8 J/(mol K) Molecular weight for Helium = 4 g/mol
Chemistry
1 answer:
Black_prince [1.1K]3 years ago
8 0

Answer:

There is 96200 J or 96 kJ of heat released.

Explanation:

<u>Step 1: </u>Data given

Mass of helium = 250 grams

Temperature = 200 K

Temperature is raised by 74 K

The heat capacity of helium = 20.8 J/mol*K

Molecular weight for helium = 4 g/mol

<u>Step 2:</u> Calculate moles of Helium

Moles of Helium = mass of Helium / molar mass of helium

Moles of helium = 250 grams / 4g/mol

Moles of helium = 62.5 moles

<u>Step 3:</u> Calculate heat

Q = n*c*ΔT  or

⇒ with Q = the heat released in Joule

⇒ with n = moles of helium = 62.5 moles

⇒ with c = the heat capacity of helium = 20.8 J/mol*K

⇒ with ΔT = the change in temperature = T2 - T1 = 74 K

Q = 62.5 mol * 20.8 J/mol*K * 74 K

Q = 96200 J = 96 kJ

Since the temperature is raised, this is an exothermic reaction. The heat is released.

There is 96200 J or 96 kJ of heat released.

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N2+3H2 → 2NH3
s2008m [1.1K]

Explanation:

N2 (g) + H2 (g) gives out NH3 (g)

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)

N2 (g) + 3H2 (g) gives out 2NH3 (g)

The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.

Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.

So what do we do? Convert to

mols (remember the hint?).

28g N2 × 1 mol N2/ 2 × 14.007) g N2

= 0.9995 mol N2

At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have

N2.

After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.

Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:

1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3

= 34.0444 g NH3

Hope it helpz~

4 0
2 years ago
Would the amount of solid magnesium increase decrease or stay the same if you added a strong acid to it?
Vlada [557]
Solid Magnesium is considered as active metal so it reacts with strong acids like HCl and H₂SO₄ liberating Hydrogen gas according to the following equations:

Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)
Mg(s) + H₂SO₄(aq) → MgSO₄(aq) + H₂(g)

so the amount of solid magnesium decrease  by addition of strong acid to it.
8 0
3 years ago
14. Would you expect each of the following atoms to gain or lose electrons when forming ions ? what ion is the most likely in ea
yanalaym [24]

Answer:

The answer to your question is below

Explanation:

Metals lose electrons and Nonmetals gain them.

a. Ra is in group IIA it will lose electrons, the ion will be Ra⁺²

b. Br is in group VIIA it will gain electrons, the ion will be Br⁻¹

c. In is in group IIIA it will lose electrons, the ion will be In⁺³

d. Te is in group VIA it will gain electrons, the ion will be Te⁻²

e. Ca is in group IIA it will lose electrons, the ion will be Ca⁺²

f. As is in group VA it will gain electrons, the ion will be As⁻³

g. Al is in group IIlA it will lose electrons, the ion will be Al⁺³

h. Rb is in group IA it will lose electrons, the ion will be Rb⁺¹

7 0
3 years ago
How do the fusion reaction in the sun compare to the fusion occurring in large atars and supernovas
r-ruslan [8.4K]
The fusion reaction in the sun is a combination of hydrogen atoms fusing to create helium. The fusion reaction in larger stars involve much heavier elements like oxygen and iron. In supernovas, often elements like gold are produced
6 0
3 years ago
How do chemists use systems and order in their work?
san4es73 [151]

Answer:

5 point) Chemists used systems and order because they study the basic unit of all forms of matter, which is the atom . However, there are several different kinds of atoms, called elements . Chemists organize these elements using the periodic table .

Explanation:

3 0
3 years ago
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