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2 years ago

Number 7 plssssssssssss

Chemistry

2 answers:

KATRIN_1 [288]2 years ago

8 0

Answer:

i think the answer is letter B.

Dmitrij [34]2 years ago

4 0

Answer:

Explanation:

Plants seek rewards for nutrients, sunlight, water, and territory necessary for survival

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Consider the group a1 element sodium atomic number 11, the group 3a element aluminum atomic number 13, and the group 7a element

Akimi4 [234]

According to there chemical properties

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3 years ago

I need the answer for this question

ch4aika [34]

I want to say A only... Hope I helped!!

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3 years ago

Sulfur dioxide is released when fossil fuels burn. What does sulfur dioxide cause? ASAP PLZ

soldi70 [24.7K]

Answer:

acid rain

Explanation:

When sulfur dioxide combines with water and air, it forms sulfuric acid, which is the main component of acid rain. Acid rain can: cause deforestation.

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3 years ago

You measure the strange insect in your yard and determine that it's 10 cm long. You want to share this new insect with other sci

blagie [28]

Answer:

A. SI units allow scientists to communicate around the world using the same

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2 years ago

In a certain city, electricity costs $0.15 per kW·h. What is the annual cost for electricity to power a lamp-post for 6.00 hours

Vanyuwa [196]

(a) Power of bulb is 100 W, converting this into kW.

$1 W=\frac{1}{1000}kW$

Thus,

$100 W =\frac{100}{1000}kW=0.1 kW$

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

$t=6\times 365=2190 h$

Electricity used will depend on power and number of hours as follows:

$E=P\times t=0.1 kW\times 2190 h=219 kW.h$

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 219 kW.h will be:

$Cost=\$ (219\times 0.15)=\$ 32.85$

Therefore, annual cost of incandescent light bulb is $\$ 32.85$

(b) Power of bulb is 25 W, converting this into kW.

$1 W=\frac{1}{1000}kW$

Thus,

$100 W =\frac{25}{1000}kW=0.025 kW$

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

$t=6\times 365=2190 h$

Electricity used will depend on power and number of hours as follows:

$E=P\times t=0.025 kW\times 2190 h=54.75 kW.h$

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 54.75 kW.h will be:

$Cost=\$ (54.75\times 0.15)=\$ 8.21$

Therefore, annual cost of fluorescent bulb is $\$ 8.21$ .

7 0

3 years ago