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matrenka [14]
2 years ago
14

Please help I will give brainliest!

Chemistry
1 answer:
Fiesta28 [93]2 years ago
7 0

Answer:

b, H2O(s) r H2O(g)

Explanation:

entropy is heat, so increase in heat would mean water gets evaporated or melted, or both in this case. so the only choice above that showed increase in heat is from solid(ice) to gas(water vaper) due to increase in heat in the reaction.

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how many moles of silicon are in 245 g of silicon? a. 8.72 mol b. 28.0 mol c. 1.10 × 10-1 mol d. 6.90 × 103 mol
il63 [147K]
Atomic mass silicon = 28.085 u

1 mol Si ---------------- 28.085 g  
?  ------------------------ 245 g

245 x 1 / 28.085 => 8.72 mol

answer A
8 0
3 years ago
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PLEASE HELP!!
sp2606 [1]
Inbox me for the answer

6 0
2 years ago
A type of physical that occurs between two electrically charged particles?
White raven [17]
Electromagnetism

Theoretically it is a branch of physics that contains two sources. Either electrically charged particles or the behavior between Neutrons and protons etc.
7 0
2 years ago
Iron has a density of 7.86 g/cm3. Calculate the volume (in dL) of a piece of iron having a mass of 4.07 kg . Note that the densi
elena-s [515]

Answer:

The volume of the piece of iron is 5.18dL.

Explanation:

The density (ρ) is equal to the mass (m) divided the volume (V).

\rho = \frac{m}{V}

If we rearrange it, we have:

V=\frac{m}{\rho }

To express the volume in dL we will need the following relations:

  • 1 dL = 0.1 L
  • 1 kg = 10³ g
  • 1 cm³ = 1 mL
  • 1mL = 10⁻³L

Then,

\rho = \frac{7.86g}{cm^{3} } .\frac{1cm^{3} }{1mL} .\frac{1mL}{10^{-3}L } .\frac{1kg}{10^{3}g } =7.86kg/L

Finally,

V=\frac{m}{\rho }=\frac{4.07kg}{7.86 kg/L} =0.518L.\frac{1dL}{0.1L} =5.18dL

5 0
3 years ago
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Given that the pressure, temperature and area of effusion is constant, the rate of effusion is inversely proportional to the square root of the molecular mass of the gas.
Mr Oxygen = 32
Mr Argon = 40
Effusion Oxygen = 1/√32
Effusion Argon = 1/√40
Effusion Oxygen / Effusion Argon = √(40) / √(32)
=√(40/32) = √(5/4) = 1.19
Thus, Oxygen will effuse 1.19 times faster than Argon. The second option is correct.
8 0
3 years ago
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