You may find the structure of compounds as well the oxidation number of sulfur in each compound written with blue color. The nonbonded electrons are represented by black dots.
Explanation:
In the methyl sulfenic acid sulfur have a oxidation number of 0, because we have +1 from carbon and -1 from hydroxil group.
In the methyl sulfinic acid sulfur have a oxidation number of +2 , because we have +1 from carbon, -1 from hydroxil group and -2 from oxygen.
In the methyl sulfonic acid sulfur have a oxidation number of +4 , because we have +1 from carbon, -1 from hydroxil group, -2 from one oxygen and -2 form the other oxygen.
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oxidation numbers
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Answer: True no need for an explanation..
Answer:
2.498g
Explanation:
First off it's important to know Avogadro's number relationship with number of moles and molar mass.
It is given as;
1 mole = 6.02 * 10^23 atoms.
A mole's weight is equal to it's molar mass. Hence the equation can be changed to;
1 mole = molar mass = 6.02 * 10^23 atoms
In this problem, molar mass of Sulphur is 32g/mol. This means 1 mole of sulphur weighs 32 g and contains 6.02 * 10^23 atoms. What mass of sulphur would then contain 4.7x10^22 of atoms?
This leads us to;
32 g = 6.02 * 10^23
x g = 4.7x10^22
Upon cross multiplication, we have;
x = (4.7x10^22 * 32) / 6.02 * 10^23
x = 24.98 * 10^-1
x = 2.498g
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Answer:
0.0198 M
Explanation:
Given data
- Mass of CaCl₂ (solute): 5.51 g
- Volume of solution: 2.50 L
Step 1: Calculate the moles of solute
The <em>molar mass of CaCl₂</em> is 110.98 g/mol. The moles corresponding to 5.51 g are:
5.51 g × (1 mol/110.98 g) = 0.0496 mol
Step 2: Calculate the molarity of the solution
<em>M = moles of solute / liters of solution</em>
M = 0.0496 mol / 2.50 L
M = 0.0198 M