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Nezavi [6.7K]
2 years ago
6

How many grams of sodium do I need to react with chlorine to make 20g of sodium chloride

Chemistry
1 answer:
NikAS [45]2 years ago
4 0

Explanation:

Na=23

cl2=35.5×2=71

NaCl=23+35.5=58.5

2Na + Cl2== 2NaCl

2. : 1

20/23=2(x)/71

(71×20)/(23×2)=x

x=30.87g

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Kipish [7]

C i took the test and got it correct

5 0
2 years ago
You have 16.7 grams of hydrogen and 15.4 grams of oxygen in a synthesis rxn. Which is the limiting reagent?
sleet_krkn [62]

Answer:

oxygen is limiting reactant

Explanation:

Given data:

Mass of hydrogen = 16.7 g

Mass of oxygen = 15.4 g

Limiting reactant = ?

Solution:

Chemical equation:

2H₂ + O₂   →   2H₂O

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 16.7 g/ 2 g/mol

Number of moles = 8.35 mol

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 15.4 g/ 32 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of both reactant with product,

                 

                             H₂           :          H₂O

                              2            :            2

                             8.35        :            8.35

                             O₂           :          H₂O

                               1            :            2

                             0.48        :        2×0.48 = 0.96 mol

The number of moles of water produced by oxygen are less so it will limiting reactant.

3 0
3 years ago
Complete the electron-dot structure of s-allylcysteine, showing all lone-pair electrons.
erastova [34]
The structural formula of <span>s-allylcysteine is shown in the picture (top figure). To create its Lewis structure, draw all its bonds between elements. Each single bond contains two electrons. There is an octet rule that must be obeyed by most elements. Each element should be surrounded with 8 electrons. The hydrogen is exempted of this rule. So, there are 4 lone pairs for the S atom, 1 lone pair for the N atom, and 2 lone pairs each for the 2 O atoms.</span>

7 0
3 years ago
A compound with the empirical formula CH 2 O has a formula mass of 180 g/mol. What is its molecular formula
olga nikolaevna [1]

Empirical formula mass

  • 12+2(1)+16
  • 28+2
  • 30g/mol

Molecular fornula mass:-180g/mol

  • n=Molecular formula mass/Empirical formula mass
  • m=180/30
  • n=6

Molecular formula:-

  • n×Empirical formula
  • 6(CH_2O
  • C_6H_12 O_6
5 0
2 years ago
Sapphires and Rubies are composed of ? <br>A. olive<br>B. turquoise<br>C. corundum<br>D. quartz​
Aleonysh [2.5K]

Answer:

c

Explanation:

it is corundum now please follow me

8 0
3 years ago
Read 2 more answers
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