Answer:
H₂S; CO₂; SiH₄
Explanation:
London dispersion forces are larger in molecules that are large and have more atoms or electrons.
A. H₂O or H₂S
H₂S. S is below O in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.
B. CO₂ or CO
CO₂. CO₂ has more atoms. It is also linear, so the molecules can get close to each other and maximize the attractive forces.
C. CH₄ or SiH₄
CH₄. Si is below C in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.
Answer:
The third one makes the most sense
I don't know why I am answering this question but assuming C-13 has a natural abundance of 1.07%:
(1.6000x10^4)(0.0107) = 171.2 = 171 atoms of C-13
Answer:
2.64 ×
J
Explanation:
I think you should mark it a physics question instead but anyway.
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The Planck equation should be applied:
E = hv , while E is energy of proton; h is Planck constant; and v is frequency.
E = 6.6 × 
× 4 × 
= 6.6 × 4 × 
= 2.64 × J
Answer:
Cd is oxidized during the discharge of the battery
Explanation:
Based on the reaction:
2 NiOOH + Cd + 2H₂O → 2Ni(OH)₂ + Cd(OH)₂
And knowing Oxygen and hydrogen never change its charge, we must to find oxidation state of Ni and Cd before and after the reaction:
<em>Ni:</em>
In NiOOH: 2 O = -2*2 = -4 + 1H = +1, = -4 + 1 = -3. And as the molecule is neutral, Ni is 3+
In Ni(OH)₂: OH = -1. As there are 2 OH = -2. That means Ni is +2
The Ni is gaining one electron, that means is been reduced
<em>Cd:</em>
Cd before reaction is as pure solid with oxidation state = 0
Cd after the reaction is as Cd(OH)₂: 2 OH = -2. That means Cd is +2
The Cd is loosing 2 electrons, that means is the species that is oxidized.
