Answer: -
Oxygen, a group 16 element with an electron configuration of 1s22s22p4, will form a __Negative___ ion in a chemical bond
Explanation: -
Oxygen has the electronic configuration of 1s2 2s2 2p4.
Number if valence electrons of oxygen = 2 + 4 = 6
Oxygen just needs 2 more electrons to have 8 electrons in it's valence shell and become stable as per Octet rule.
Thus oxygen will accept 2 electrons during formation of a chemical bond.
Due to this it will have negative charge and form a negative ion or anion in a chemical bond.
Answer:
No they should stop.
The simple fact is that nuclear power is terribly dangerous. From a health and safety standpoint, it is utterly irrational for us to continue to generate electricity by splitting the atom. Nuclear power is unreasonably expensive. When all of its costs are considered, it becomes clear that nuclear power is unaffordable.
Explanation:
Hope this helps
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Answer:
4.186 L
Explanation:
Using the pv=nrt equation and converting the grams of O2 into mols. After finding the number of mols by dividing 5.98 by 32 (2*the atomic weight of O) you plug that into the equation. So then you have 1*V=.186875*.08206*273 then you rearrange the equation to solve for v and get 4.186 L
Answer:
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<em>a) Balanced chemical equation:</em>
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<em>b) Theoretical yield:</em>
c) % yield:
Explanation:
The complete question is:
<em>In a particular reaction 6.80g of dinitrogen trioxide gas (N₂0₃) was actually produced by reacting 8.75g of oxygen gas (O₂) with excess nitrogen gas (N₂)</em>
<em>a) Write a balanced chemical equation for the reaction. Be sure to include physical states in the equation.</em>
<em>b) Calculate the theoretical yield (in grams) of dinitrogen trioxide: Use dimensional analysis</em>
<em>c) Calculate the % yield of the product</em>
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<h2>Solution</h2>
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<em>a) Write a balanced chemical equation for the reaction. Be sure to include physical states in the equation.</em>
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<em> </em><em />
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Check the balance:
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Atom Left-handside Right-hand side
N 2×2=4 2×2=4
O 3×2=6 2×3=6
- Mole ratio: it is the ratio of the coefficients of the balanced equation
<em>b) Calculate the theoretical yield (in grams) of dinitrogen trioxide: Use dimensional analysis</em>
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<u>1. Convert 8.75 g of O₂(g) to number of moles</u>
- number of moles = mass in grams / molar mass
- molar mass of O₂ = 15.999g/mol
- number of moles = 8.75g / 15.999 g/mol = 0.5469 mol O₂
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<u>2. Use dimensional analysis to calculate the maximum number of moles of N₂O₃(g) that can be produced</u>
<u>3. Convert to mass in grams</u>
- mass = number of moles × molar mass
- molar mass of N₂O3 = 76.01g/mol
- mass = 0.3646mol × 76.01g/mol = 27.7g N₂O3
<em>c) Calculate the % yield of the product</em>
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Formula:
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- %yield = (actual yield/theoretical yield)×100
Substitute and compute:
- % yield = (6.80g/27.7g)×100 = 24.5%
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