M<span>olar mass Hg = 200.5920g/mol </span>
<span>Hg = 24.1/200.5920 = 0.120mol </span>
<span>234.32K liquid to 25C (298.15K) liquid </span>
<span>h = (0.120)(28.0)(298.15 - 234.32) = 214.4688 J </span>
<span>234.32K liquid to 234.32K solid </span>
<span>h = (0.120)(2.29) = 0.2748 kj </span>
<span>total heat = 0.2145 + 0.2748 = 0.4893 kJ</span>
Answer:
3 M
Explanation:
Given data
- Moles of sodium hydroxide (solute): 5 moles
- Volume of solution: 2 liters
We can calculate the molar concentration, or molarity (M), of the solution using the following expression.
M = moles of solute / volume of solution (in liters)
M = 5 moles / 2 L
M = 2.5 M ≈ 3 M (if we round off to 1 significant figure)
The chemical symbol for sodium bicarbonate is NaHCO3. Its molar mass is 84 g/mol. In each of one mol of sodium bicarbonate their is one mole of carbon dioxide with the molar mass of 44 grams per mol. We determine the number of moles in 0.10 g of sodium bicarbonate.
n sodium bicarbonate = (0.10 g) / (84 grams / mol)
= 1.19 x 10-3 moles sodium bicarbonate
Therefore, there are also 1.19 x 10-3 moles of carbon dioxide.
I think that beryllium is formed in alcohol I think
The correct answer for the question that is being presented above is this one: "C) The reaction is spontaneous at high temperatures."
Since dH is positive and dS ~ 0 then -TdS ~ 0, meaning dG will always be greater than 0 so t<span>he reaction is spontaneous at high temperatures.</span>
