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2 years ago

How many electrons are typically involved in bonding for group 1, group 2 and group 3 elements?

1 answer:

8 0

Here, we are required to determine how many electrons are typically involved in bonding for group 1, group 2 and group 3 elements and How many electrons are typically involved in bonding for group 6, 7 and 8 elements.

For group 1: Only one electron.
For group 2: Only two electrons
For group 3: Only 3 electrons
For group 6: Only 2 electrons
Fir group 7: Only 1 electron
For group 8: No electron

The Valence electrons are the electrons which are available for bonding and chemical reactions in elements.

The Valence electrons are the electrons which are available for bonding and chemical reactions in elements.However, not all Valence electrons are actively involved in bonding. This is evident in the group 7(halogens) elements, although they have 7 Valence electrons, only one is actively involved in bonding.

For group 1 elements: They have only one Valence electron and it is actively involved in bonding (ionic bonding)

For group 2 elements: They have only two Valence electron and both are actively involved in bonding (ionic bonding)

For group 3 elements: They have only three Valence electrons and all three are typically used for bonding.

For group 6 elements: They have 6 Valence electrons and are electronegative. As such, they only need to receive 2 electrons from an electropositive element and consequently, they only contribute two electrons into the bonding. As such, only 2 electrons are typically used for bonding.

For group 7: They have 7 Valence electrons and are highly electronegative. As such, they only need to receive 1 electrons from an electropositive element and consequently, they only contribute 1 electrons into the bonding. As such, only 1 electrons are typically used for bonding.

For group 8: They have a full octet configuration and are unreactive. Therefore, no electron is typically used for bonding.

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1. Mg2+ and Ca2+ are in the same group on the periodic table. In terms of electronic

finlep [7]

Answer:

Se detailed explanation.

Explanation:

Hello,

In this case, since both magnesium and calcium ions are in group IIA, we can review the following similar properties:

- Since both calcium and magnesium are in group IIA they have two valence electrons, it means that the both of them have two electrons at their outer shells.

- They are highly soluble in water when forming ionic bonds with nonmetals such as those belonging to halogens and oxygen's family.

- Calcium has 18 electrons and magnesium 10 which are two less than the total protons (20 and 12 respectively) since the both of them have lost two electrons due their ionized form.

- Their electron configurations are:

$Ca^{20}=1s^2,2s^2,2p^6,3s^3,3p^6,4s^2\\\\Mg^{12}=1s^2,2s^2,2p^6,3s^2$

It means that the both of them are at the $s$ region since it is the last subshell at which their electrons are.

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3 years ago

Write out the word equations for these reactions. ) Hydrogen reacts with oxygen to form water.

ale4655 [162]

Answer:

H2O

Explanation:

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3 years ago

If the H+ ion concentrati on in an aqueous solution is 0.0010 M, why is it not possible for the OH− ion concentration to be 1.0

spayn [35]

Answer:

im not sure sry

Explanation:

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2 years ago

Fe3+(aq)+6H2O(l)⇌Fe(H2O)63+(aq) : F e 3 + ( a q ) + 6 H 2 O ( l ) ⇌ F e ( H 2 O ) 6 3 + ( a q ) : blank is the Lewis acid and bl

Tasya [4]

Answer:

Lewis acid- Fe3+

Lewis base- water molecule

Explanation:

Acids and bases have been defined in diverse ways. There have been definitions put forward by Arrhenius, Brownstead and Lowry as well as Lewis. Each definition his useful in its own way.

Lewis acids are lone pair acceptors such as metal ions. This implies that in the particular instance of this reaction, Fe3+ is the lewis acid.

Similarly, a Lewis base is a lone pair donor, all ligands are lone pair donors since they donate one or more lone pairs of electrons to Lewis acids. In the particular instance of this reaction, the Lewis base is the water molecule.

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3 years ago

Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm8 at 27 ∘C. (R =

maxonik [38]

Answer:

Total pressure = 56.77 bar

Explanation:

Given data:

Mass of dioxygen = 8 g

Mass of dihydrogen = 4 g

Volume of vessel = 1 dm³

Temperature = 27°C (27+273 = 300 K)

R = 0.083 bar.dm³ / mol.K

Total pressure = ?

Solution:

Number of moles of dioxygen:

Number of moles = mass/molar mass

Number of moles = 8 g/ 32 g/mol

Number of moles = 0.25 mol

Pressure of dioxygen:

PV = nRT

P = nRT/V

P = 0.25 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 6.97 bar.dm³ /1 dm³

P = 6.97 bar

Number of moles of dihydrogen:

Number of moles = mass/molar mass

Number of moles = 4 g/ 2 g/mol

Number of moles = 2 mol

Pressure of dihydrogen:

PV = nRT

P = nRT/V

P = 2 mol × 0.083 bar.dm³ / mol.K × 300 K / 1 dm³

P = 49.8 bar.dm³ /1 dm³

P = 49.8 bar

Total pressure of mixture in a vessel:

Total pressure = P (O₂) + P(H₂)

Total pressure = 6.97 bar + 49.8 bar

Total pressure = 56.77 bar

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3 years ago