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2 years ago

How many electrons are typically involved in bonding for group 1, group 2 and group 3 elements?

1 answer:

8 0

Here, we are required to determine how many electrons are typically involved in bonding for group 1, group 2 and group 3 elements and How many electrons are typically involved in bonding for group 6, 7 and 8 elements.

For group 1: Only one electron.
For group 2: Only two electrons
For group 3: Only 3 electrons
For group 6: Only 2 electrons
Fir group 7: Only 1 electron
For group 8: No electron

The Valence electrons are the electrons which are available for bonding and chemical reactions in elements.

The Valence electrons are the electrons which are available for bonding and chemical reactions in elements.However, not all Valence electrons are actively involved in bonding. This is evident in the group 7(halogens) elements, although they have 7 Valence electrons, only one is actively involved in bonding.

For group 1 elements: They have only one Valence electron and it is actively involved in bonding (ionic bonding)

For group 2 elements: They have only two Valence electron and both are actively involved in bonding (ionic bonding)

For group 3 elements: They have only three Valence electrons and all three are typically used for bonding.

For group 6 elements: They have 6 Valence electrons and are electronegative. As such, they only need to receive 2 electrons from an electropositive element and consequently, they only contribute two electrons into the bonding. As such, only 2 electrons are typically used for bonding.

For group 7: They have 7 Valence electrons and are highly electronegative. As such, they only need to receive 1 electrons from an electropositive element and consequently, they only contribute 1 electrons into the bonding. As such, only 1 electrons are typically used for bonding.

For group 8: They have a full octet configuration and are unreactive. Therefore, no electron is typically used for bonding.

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For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0

3 years ago

I. Three different representations of glucose are given below. Identify each type of model.

Free_Kalibri [48]

Answer:

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fischer projection has the atoms on the side coming out of the plane, the atoms at the ends going behind (going away from you)

bond line notation Is the most common it does not show the C or H bonds but instead carbons are represented by the bends

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2 years ago

Given the law of conservation of energy, what happens when a 200°C iron bar is placed in thermal contact with a 30°C block of wo

kozerog [31]

Answer:

The correct answer is A Energy leaves the iron bar and enters the wood until the temperature are equal.

Explanation:

According to the law of conservation of energy or the first law thermodynamics energy neither be created nor destroyed, energy is transferred from one form to another form.

Here iron bar is placed in wood block energy is transferred from iron bar to wood until the temperatures are equal.

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3 years ago

Molecular formula for C4H10

Gnesinka [82]

I think this is what you mean:

H H H H
H-C-C-C-C-H
H H H H

OR

CH3CH2CH2CH3

If not, clarify and I will be happy to help.

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3 years ago

What property is used to organize elements on the periodic table?

erma4kov [3.2K]

Atomic Number is used to organize the periodic table.

Hope this helps

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