FeOH2 = 73.8602753 g/mol
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Answer:
53.491 g/mol
Explanation:
Create the chemical compound and find each individual element's molar mass. Lastly, add them up.
To complete the balancing of the following combustion reaction, we must do elemental balances. For C, there is 5 on the left side hence there should be 5 CO2. For H, H20 should be 9/2. Next we balance O. on theright side we find a total of 29/2. So the o2 on the left side should be 29/4. To have whole number stoich.coeff. we multiply the numbers by 4, hence answer is
4C5H9O + 9O2= 20 O2 + 18 H20.
Answer:
15.89%
Explanation:
To calculate the percentage of carbon in BeC2O4•3H2O, first we calculate the molar mass of BeC2O4•3H2O
MM of BeC2O4•3H2O = 9+(12x2)+(4x16)+3(2+16) = 9+24+64+54 =151g/mol
Mass of C in BeC2O4•3H2O = 2x12 = 24g
%Mass of carbon in BeC2O4•3H2O = (24/151) x 100
= 15.89%
Answer:
d. can be separated into components
it's the answer and i hope it helps you
