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Novay_Z [31]
2 years ago
11

The chemical formula for sodium citrate is Nag Cs H5O7

Chemistry
1 answer:
Yuliya22 [10]2 years ago
3 0

Answer:

C. Sodium citrate is a compound with a total of 21 atoms

Explanation:

Here's to help reassure you that the answer is correct, look at the picture

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What are three ways heat is transfered
Gre4nikov [31]

Answer:

Conduction, Convection and Radiation

Explanation:

6 0
3 years ago
Read 2 more answers
12-How many elements are in the mixture pictured below?<br> A-7<br> O B-4<br> C-3<br> D-2
vovikov84 [41]

Answer:

C

Explanation:

3

Because you don't count the dots. You count how many colors there are. Which are Blue, Red, and Black.

Hope this helped!

4 0
3 years ago
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What is the molarity of a solution that is made by mixing 35.5 g of Ba(OH)2 in 325 ml of solution?
choli [55]

Answer:

M=0.638M

Explanation:

Hello!

In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:

n=35.5g Ba(OH)_2*\frac{1molBa(OH)_2}{171.34gBa(OH)_2}\\\\n=0.207mol

Then, the liters of solution:

V=325mL*\frac{1L}{1000mL} =0.325L

Finally, the molarity turns out:

M=\frac{0.207mol}{0.325L}\\\\M=0.638M

Best regards!

5 0
3 years ago
Transition metals when moving from left to right on the periodic table?
Ierofanga [76]

Answer:

True

Explanation:

5 0
3 years ago
What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?​
tatiyna

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

6 0
3 years ago
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