Answer:
the tendency of a body to float or to rise when submerged in a fluid testing an object's buoyancy.
Explanation:
The meaning is from Merriam Webster for more such unique nd it also has easy meanings you can download that
(Source Merriam Webster)
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Answer
a) Using dimensional analysis we cannot derive the relation, But we can check the correctness of the formula.
![s = u t +\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s%20%3D%20u%20t%20%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
now, L H S
s = distance
dimension of distance = [M⁰L¹T⁰]
now, equation on the right hand side
R H S
u = speed
u = m/s
Dimension of speed = [M⁰L¹T⁻¹]
dimension of time
t = sec
Dimension of time = [M⁰L⁰T¹]
Dimension of 'ut' = [M⁰L¹T⁻¹][M⁰L⁰T¹]
= [M⁰L¹T⁰]
now, acceleration= a
a = m /s²
dimension of acceleration = [M⁰L¹T⁻²]
dimension of (at²) = [M⁰L¹T⁻²][M⁰L⁰T¹][M⁰L⁰T¹]
= [M⁰L¹T⁰]
hence, the dimension are balanced.
so, L H S = R H S
b) Moment of inertia of hollow sphere = ![\dfrac{2}{3}Mr^2](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B3%7DMr%5E2)
Moment of inertia of solid sphere = ![\dfrac{2}{5}Mr^2](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B5%7DMr%5E2)
we know,
![\tau = I \alpha](https://tex.z-dn.net/?f=%5Ctau%20%3D%20I%20%5Calpha)
![\alpha=\dfrac{\tau}{I}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B%5Ctau%7D%7BI%7D)
Torque is the force that causes rotation
If the same amount of torque is applied to both spheres the sphere with bigger moment of inertia would have smaller angular velocity.
Thus the solid sphere would accelerate more.
Answer:
The work done is zero
Explanation:
No work is performed or required in moving the positive charge from point A to point B
Answer:
Fluorine
Explanation:
Halogens is the group right before Noble Gases, or Group 17. They consist of (from Period 1 to 7):
2 - Fluorine
3 - Chlorine
4 - Bromine
5 - Iodine
6 - Astatine
7 - Tennessine
We can see from the Periodic Table of Elements that Fluorine will be our answer.
Answer:
d = 136.7 ft
Explanation:
Because the truck move with uniformly accelerated movement we apply the following formula:
vf²=v₀²+2*a*d Formula (1)
Where:
d:displacement in meters (ft)
v₀: initial speed in ft/s
vf: final speed in ft/s
a: acceleration in ft/s²
Data
v₀ = 44.0 mi/h
1milla = 5280 ft
1h = 3600 s
v₀ = 44*(5280 ft) / (3600 s) = 64.5 ft/s
vf = 0
d = 47.0 ft
Calculation of the acceleration of the truck
We replace data in the formula (1) :
vf²=v₀²+2*a*d
0 = (64.5)²+2*a*(47)
-(64.5)² = (94)*a
a = -(64.5)² / 94
a = - 44.26 ft/s²
The acceleration (a) it's negative (-) because the truck is braking
Calculation of the minimum stopping distance of the truck to v₀ = 75.0 mi/h
v₀ = 75 mi/h = 75* (5280 ft) / (3600s) = 110 ft/s
We replace v₀ = 110 ft/s and a = - 44.26 ft/s² in the formula (1):
vf²=v₀²+2*a*d
0 = (110)²+2*(-44.26)*d
88.52*d = (110)²
d = (110)² / (88.52)
d = 136.7 ft