I REALLY NEED HELP.....PLEASE SOMEONE!!!

1 answer:

7 0

<span>If a plane has a velocity of 300 km/h and a tailwind of 20 km/h, then the vectors of both forces would add (assuming that the tailwind is blowing exactly at the airplanes back) to a total of 320 km/h. Hope it helps

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The frequency of a sound wave was measured to be 351 Hz. If you know that the speed of sound in air was 343 m/s, then determine

netineya [11]

Answer:

wavelength of the sound wave will be 0.977 m

Explanation:

We have given frequency of the sound wave f = 351 Hz

Speed of the sound wave v = 343 m/sec

We have to find the wavelength of the sound wave

We know that velocity of the sound wave is given by $v=\lambda f$

So wavelength of the sound wave $\lambda =\frac{v}{f}=\frac{343}{351}=0.977m$

So wavelength of the sound wave will be 0.977 m

4 0

3 years ago

Help ASAP Electroscope problem

JulijaS [17]

Answer:

An excess of positive (or negative) charge causes the leaves to diverge

Bringing a neutral rod in the vicinity of the electroscope will cause some of the positive charge to leave the leaves (making the electrically neutral rod negative at the tip) causing the leaves to converge.

3 0

3 years ago

Marking brainliest help pls the formula are there to help ^

natta225 [31]

Answer:

Explanation:

Look at the equation for Potential Energy. PE = mass times gravity times the height. Filling in and solving for h:

34.3 = .5(9.8)h so

34.3 = 4.9h so

h = 7 meters

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3 years ago

Antimony consists of two major isotopes with the following atomic masses: 121Sb (120.904 amu) and 123Sb (122.904 amu). The avera

Bad White [126]

Answer:

121Sb=57.2%

123Sb=42.8%

Explanation:

We are given that

Atomic mass of 121Sb=120.904 amu

Atomic mass of 123Sb=122.904 amu

Average atomic mass of antimony=121.760 amu

We have to find the percent of each of the isotope.

Let x be the percent of 121Sb and 1-x be the percent of 123Sb.

Using formula of average atomic weight

Average atomic weight=atomic weight of 121Sb $\times$ percentage abundance of isotope 121Sb+atomic weight of 123Sb $\times$ percentage abundance of isotope 123Sb