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cestrela7 [59]
3 years ago
5

I REALLY NEED HELP.....PLEASE SOMEONE!!!

Physics
1 answer:
suter [353]3 years ago
7 0
<span>If a plane has a velocity of 300 km/h and a tailwind of 20 km/h, then the vectors of both forces would add (assuming that the tailwind is blowing exactly at the airplanes back) to a total of 320 km/h. Hope it helps

</span>
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What force to be required to accelerate a car of mass 120 kg from 5 m/s to 25m/s in 2s​
Ira Lisetskai [31]

Answer:1200

Explanation:

F=ma =m(Vf-Vi)/t

F=120(25-5)/2 =1200N

4 0
3 years ago
Ree is 27 inches tall on her first birthday. She grows around 6 inches per year after that. What is the rate of change for the s
RSB [31]

Answer:

6

Explanation:

The rate of change in this scenario corresponds to the number of inches that Ree grows every year. Basically, Ree's height can be written as a linear equation as follows:

y=mx+q

where

x is the number of years after the first birthday

y is the height in inches

q = 27 is the height of Ree on her first birthday

m = 6 is the inches gained by Ree at each birthday

So the equation can also be rewritten as

y = 6x + 27

4 0
4 years ago
Read 2 more answers
Taking the resistivity of platinoid as 3.3 x 10-7 m, find the resistance of 7.0 m of platinoid wire of average diameter 0.14 cm.
mr_godi [17]

Answer:

1.5 \Omega

Explanation:

The resistance of a wire is given by the equation:

R=\rho \frac{L}{A}

where

\rho is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

In this problem, we have a wire of platinoid, whose resistivity is

\rho = 3.3\cdot 10^{-7} \Omega m

The length of the wire is

L = 7.0 m

And its radius is

r=\frac{0.14 cm}{2}=0.07 cm = 7\cdot 10^{-4} m, so the cross-sectional area is

A=\pi r^2=\pi(7\cdot 10^{-4})^2=1.54\cdot 10^{-6}m^2

Solving for R, we find the resistance of the wire:

R=(3.3\cdot 10^{-7})\frac{7.0}{1.54\cdot 10^{-6}}=1.5 \Omega

3 0
3 years ago
ASAP <br> What is elastic potential energy?
chubhunter [2.5K]

Answer:

Elastic potential energy is stored when materials stretch or compress. Examples of it include springs, rubber bands, and slingshots.

Explanation:

3 0
3 years ago
The ability to distinguish between acceleration and velocity will be critical to your understanding of many other concepts in th
Sauron [17]

Answer:

Object could only be moving with increasing speed.

Explanation:

Let us consider the general formula of acceleration:

a = (Vf - Vi)/t

Vf = Vi + at   -------- equation 1

where,

Vf = Final Velocity

Vi = Initial Velocity

a = acceleration

t = time

<u>FOR POSITIVE ACCELERATION:</u>

Vf = Vi + at

since, both acceleration and time are positive quantities. Hence, it means that the final velocity of the object shall be greater than the initial velocity of the object.

Vf > Vi

It clearly shows that if an object moves with positive acceleration. <u>It could only be moving with increasing speed.</u>

Solving the same equation for negative acceleration shows that the final velocity will be less than initial velocity and object will be moving with decreasing speed.

And for the constant velocity final and initial velocities are equal and thus, acceleration will be zero.

7 0
3 years ago
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