Explanation:
It is given that,
Mass of the rim of wheel, m₁ = 7 kg
Mass of one spoke, m₂ = 1.2 kg
Diameter of the wagon, d = 0.5 m
Radius of the wagon, r = 0.25 m
Let I is the the moment of inertia of the wagon wheel for rotation about its axis.
We know that the moment of inertia of the ring is given by :


The moment of inertia of the rod about one end is given by :

l = r


For 6 spokes, 
So, the net moment of inertia of the wagon is :


So, the moment of inertia of the wagon wheel for rotation about its axis is
. Hence, this is the required solution.
Answer:
The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp
Explanation:
<u>Polar moment of Inertia</u>

= 0.14374 in 4
<u>Maximum sustainable torque on the solid circular shaft</u>

=
= 3658.836 lb.in
=
lb.ft
= 304.9 lb.ft
<u>Maximum sustainable torque on the tubular shaft</u>

= 
= 3334.8 lb.in
=
lb.ft
= 277.9 lb.ft
<u>Maximum sustainable power in the solid circular shaft</u>

= 
= 4023.061 lb. ft/s
=
hp
= 7.315 hp
<u>Maximum sustainable power in the tubular shaft</u>

= 
= 3666.804 lb.ft /s
=
hp
= 6.667 hp
Answer:
If F is a constant, we can take f = 1
f = m×a
ma = 1
therefore we can say that force is hence proportinal to the product of mass and acceleration.
Answer:
Inertia
F=ma
Action, reaction
All of the above
A heavy object requires more force to push than a lighter object.