What is the angle between the electric field and the axis of the filter?

1 answer:

7 0

In this question we will use the Malus Law, the formula of it is I = lo*cos^2(alpha). We will say that the given percentage of the intensity of a polarized light wave passes through a polarizing filter is 14%.
I = Io*cos^2(alpha)
then cos^2(alpha) = 0.14 alpha = arccos(sqrt(0.14)) = 68.03°
The answer in this question is 68.03°

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