Answer:
(a). The eye's near point is 68.98 cm from the eye.
(b). The eye's far point is 33.33 cm from the eye.
Explanation:
Given that,
Power = 2.55 D
Object distance = 25 cm for near point
Object distance = ∞ for far point
Suppose where is the far point of an eye for which a contact lens with a power of -3.00 D is prescribed for distant vision?
(a) We need to calculate the focal length
Using formula of power
Put the value into the formula
We need to calculate the image distance
Using formula of lens
Put the value into the formula
The eye's near point is 68.98 cm from the eye.
(b). We need to calculate the focal length
Using formula of power
Put the value into the formula
We need to calculate the image distance
Using formula of lens
Put the value into the formula
The eye's far point is 33.33 cm from the eye.
Hence, (a). The eye's near point is 68.98 cm from the eye.
(b). The eye's far point is 33.33 cm from the eye.