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ra1l [238]
2 years ago
7

What number on this diagram indicates the trend line? A. 1 B. 2 C. 4 D. 7

Physics
1 answer:
Alex2 years ago
4 0

Answer:7

Explanation:

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A football is kicked from the ground with a velocity of 38m/s at an angle of 40 degrees and eventually lands at the same height.
Anastasy [175]

Initially, the velocity vector is \langle 38cos(40^{\circ}),38sin(40^{\circ}) \rangle=\langle 29.110, 24.426 \rangle. At the same height, the x-value of the vector will be the same, and the y-value will be opposite (assuming no air resistance). Assuming perfect reflection off the ground, the velocity vector is the same. After 0.2 seconds at 9.8 seconds, the y-value has decreased by 4.9(0.2)^2, so the velocity is \langle 29.110, 24.426-0.196 \rangle = \langle 29.110, 24.23 \rangle.

Converting back to direction and magnitude, we get \langle r,\theta \rangle=\langle \sqrt{29.11^2+24.23^2},tan^{-1}(\frac{29.11}{24.23}) \rangle = \langle 37.87,50.2^{\circ}\rangle

4 0
3 years ago
Because of the curvature of the earth, the maximum distance D that you can see from the top of a tall building of height h is es
mojhsa [17]

Answer:

 D = 9.9 10⁶ mi

Explanation:

In the exercise they give the expression for maximum viewing distance

       D = 2 r h + h²

Ask for this distance for a height of 1100 feet

Let's calculate

        D = 2 3960 1100 + 1100²

        D = 8.712 10⁶ + 1.21 10⁶

        D = 9.92 10⁶ mi

         D = 9.9 10⁶ mi

8 0
3 years ago
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ivann1987 [24]

Answer:

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8 0
3 years ago
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What is the weight of an astronaut who has a mass of 90 kg on the moon? (Note: acceleration due to gravity of the moon is 1.62 N
motikmotik

Answer:

W = 145.8 [N]

Explanation:

To solve this problem we must remember that weight is defined as the product of mass by gravity, in this case lunar gravity.

W = m*g

where:

m = mass = 90 [kg]

g = gravity acceleration = 1.62 [kg/m²]

W = 90*1.62

W = 145.8 [N]

8 0
3 years ago
If you can throw a stone straight up to height h, what’s the maximum horizontal distance you could throw it over level ground?
Mariana [72]
To answer this question, first we take note that the maximum height that can be reached by an object thrown straight up at a certain speed is calculated through the equation,
                            Hmax = v²sin²θ/2g
where v is the velocity, θ is the angle (in this case, 90°) and g is the gravitational constant. Since all are known except for v, we can then solve for v whichi s the initial velocity of the projectile. 

Once we have the value of v, we multiply this by the total time traveled by the projectile to solve for the value of the range (that is the total horizontal distance). 
8 0
2 years ago
Read 2 more answers
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