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2 years ago

Which sentence best describes the particles that make up a liquid?

Physics

1 answer:

Daniel [21]2 years ago

4 0

I had a teat and the answer was A

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Imagine you are sitting on a surfboard in the ocean, waiting to catch a big wave. When the ocean is still, you are sitting at a

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B. What is the frequency

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3 years ago

An element has 4 protons, 5 neutrons, and 4 electrons. What is the atomic mass of the element? 4 5 8 9

alex41 [277]

at mass = protons+neutrons=9

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3 years ago

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A 20 cm tall object is placed in front of a concave mirror with a radius of 31 cm. The distance of the object to the mirror is 9

Aloiza [94]

Answer:

The focal length of the concave mirror is -15.5 cm

Explanation:

Given that,

Height of the object, h = 20 cm

Radius of curvature of the mirror, R = -31 cm (direction is opposite)

Object distance, u = -94 cm

We need to find the focal length of the mirror. The relation between the focal length and the radius of curvature of the mirror is as follows :

R = 2f

f is the focal length

$f=\dfrac{R}{2}$

$f=\dfrac{-31}{2}$

f = -15.5 cm

So, the focal length of the concave mirror is -15.5 cm. Hence, this is the required solution.

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3 years ago

A 100kg car starts from rest at the top of a hill with a height of 50m. which of the following is this cars kinetic energy at th

Anarel [89]

Explanation:

KE =1/2 MV^2

HOPE YOU COULD SOLVE FROM NOW..

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3 years ago

A small 0.14 kg metal ball is tied to a very light (essentially massless) string that is 0.9 m long. The string is attached to t

Vsevolod [243]

Answer:

a) v=2.743m/s

b) $a_c = 8.363m/s^2$

c) T=2.543N

Explanation:

First, calculate the height of the ball at the starting point:

$y' = 0.9cos(55)$

$y' = 0.516$

At this point, just in the moment the ball is released, all the energy of the system is potencial gravitational energy. When it is at the bottom all the potencial energy is transformed into kinetic energy:

$E_p=E_k\\mgh=\frac{mv^2}{2}$

Solving for v:

$v=\sqrt{2gh}$

if h is the height loss: (l-y')

v=2.743m/s

The centripetal acceleration is the acceleration caused by the tension force exercised by the string, and is pointing outside of the trayectory path (at the lowest point, directly dawn):

$a_c=\frac{v^2}{r}$

$a_c = 8.363m/s^2$

To calculate tension, just make the free body diagram of forces in the ball, noticing the existence of the centripetal acceleration:

$\sum{F_y}=ma_c=T-W\\T=ma_c+W\\T=m(a_c+g)\\T=0.14(8.363+9.8)\\T=2.543N$

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4 years ago