Ask question

Ask question

All categories

julia-pushkina [17]

3 years ago

9

Which sentence best describes the particles that make up a liquid?

1 answer:

Daniel [21]3 years ago

4 0

I had a teat and the answer was A

You might be interested in

The universe could be considered an isolated system because

cricket20 [7]

a) many people think that no energy or matter exists outside the universe.

An isolated system is defined as a system that does not interact with its surroundings. This is the reason that its total energy and mass remains constant. Moreover, t<span>otal</span><span> momentum in a system is conserved for collisions occurring in </span><span>isolated systems.</span>

8 0

3 years ago

A large crate with mass m rests on a horizontal floor. The static and kinetic coefficients of friction between the crate and the

____ [38]

Answer:

Explanation:

Check attachment for solution

6 0

3 years ago

How is weather and climate alike

Zarrin [17]

Both climate and weather measure conditions in the atmosphere.

6 0

3 years ago

A force of 6.0 Newton’s gives a 2.0kg block an acceleration of 3.0m/s to the right. The force of friction acting on the block is

DochEvi [55]

The force of friction is zero.
Using F = m a = the force needed is 6 N which means no friction can be acting.

3 0

4 years ago

A coil of 1,000 turns encloses an area of 85 cm^2. It is rotated in 0.090 s from a position where its plane is perpendicular to

Maurinko [17]

Answer:

The average emf induced in the coil is $5.6\times10^{-3}\ mV$ .

Explanation:

Given that,

Number of turns = 1000 turns

Area = 85 cm²

Time = 0.090 s

Its plane is perpendicular to Earth's magnetic field.

Angle = 0°

Magnetic strength $B=6.0\times10^{-5}\ T$

We need to calculate the magnetic flux

Using formula of magnetic flux

$\phi=BA\cos\theta$

Put the value into the formula

$\phi=6.0\times10^{-5}\times85\times10^{-4}\times\cos0^{\circ}$

$\phi =6.0\times10^{-5}\times85\times10^{-4}\times1$

$\phi=5.1\times10^{-7}\ Wb$

We need to calculate the average emf induced in the coil

$\epsilon=\dfrac{d\phi}{dt}$

Put the value into the formula

$\epsilon=\dfrac{5.1\times10^{-7}}{0.090}$

$\epsilon=0.0000056\ N$

$\epsilon =5.6\times10^{-3}\ mV$

Hence, The average emf induced in the coil is $5.6\times10^{-3}\ mV$ .

3 0

3 years ago