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swat32
3 years ago
15

A person jumps from the roof of a house 3.1-m high. When he strikes the ground below, he bends his knees so that his torso decel

erates over an approximate distance of 0.70 m. If the mass of his torso (excluding legs) is 42kg .
Part A
Find his velocity just before his feet strike the ground.
Express your answer using two significant figures. Enter positive value if the velocity is upward and negative value if the velocity is downward.
Physics
1 answer:
Sveta_85 [38]3 years ago
3 0
Part A

Free fall motion
h = 3.1 m

Equation: Vf = √(2gh) = √(2*9.8 m/s^2 * 3.1 m) = 7.8 m/s

That is the only part in the question.
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Answer:

See the explanation below

Explanation:

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density = m/v

where:

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If we change the volume of a body by reducing its size, its mass will also decrease proportionally with a density as seen in the equation.

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To understand this concept more clearly, let's use the following example:

We know that the density of water is equal to 1000 [kg/m^3], that is, 1 cubic meter of water contains 1000 kilograms of water, using the equation.

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v = 500/1000

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We can see that the volume of water has halved. Since the mass of water was reduced by half. That is, the relationship between mass and volume is proportional to the density of the material or substance.

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