Answer:
0.25m/s
Explanation:
Given parameters
m₁ = 5kg
v₁ = 1.0m/s
m₂ = 15kg
v₂ = 0m/s
Unknown:
velocity after collision = ?
Solution:
Momentum before collision and after collision will be the same. For inelastic collision;
m₁v₁ + m₂v₂ = v(m₁ + m₂)
Insert parameters and solve for v;
5 x 1 + 15 x 0 = v (5 + 15 )
5 = 20v
v =
= 0.25m/s
Force = (mass) x (acceleration)
5 N = (9 kg) x (acceleration)
Divide each side
by 9 kg : 5 N / 9 kg = acceleration
Acceleration = (5/9) kg-meter/sec²-kg
= 0.555... m/s² .
Answer: The correct answers are (A) and (C).
Explanation:
The expression from electrostatic force is as follows;

Here, F is the electrostatic force, k is constant, r is the distance between the charges and
are the charges.
The electrostatic force follows inverse square law. It is inversely proportional to the square of the distance between the charges. It is directly proportional to the product of the charges.
Like charges repel each other. There is a force of electrostatic repulsion between the like charges. Unlike charges attract each other. There is a force of electrostatic attraction between unlike charges.
The charges are induced on the neutral object when it is placed nearby the charged object without actually touching it.
Therefore, the true statements from the given options are as follows;
Like charges repel.
Unlike charges attract.
Answer:
The pressure difference between two pipe is
Pa
Explanation:
Density

Speed in one pipe

Speed in second pipe

According to the bernoulli equation,
The pressure difference is given by,


![P_{2} - P_{1} = \frac{1}{2} \times 1165 \times[ (4.53)^{2}- (1.77)^{2}]](https://tex.z-dn.net/?f=P_%7B2%7D%20-%20P_%7B1%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%201165%20%5Ctimes%5B%20%284.53%29%5E%7B2%7D-%20%281.77%29%5E%7B2%7D%5D)
Pa
Therefore, the pressure difference between two pipe is
Pa