The answer to this is aluminum foil.
<span>Self-monitoring would be the best way to </span><span>determine your own correct intensity level. I hope this helps! <3
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Electricity is NOT a part of electromagnetic spectrum.
An electromagnetic spectrum contains electromagnetic radiations arranged according to frequencies and wavelength.
<h2>Further Explanation
</h2><h3>Electromagnetic waves </h3>
- Electromagnetic waves are types of waves that do not require a material medium for transmission.
- These waves are mostly transverse in nature, which means the direction of transmission is perpendicular to the direction of vibration of particles.
- They include, light waves, radio waves, x-rays, infra-red, etc.
<h3>Electromagnetic spectrum
</h3>
- An electromagnetic wave shows electromagnetic waves arranged according to frequencies and wavelength.
- Electromagnetic spectrum contains electromagnetic waves: Gamma rays, x-rays, Ultraviolet, Visible light, infra-red, microwaves, and radio waves.
- The electromagnetic spectrum is divided into various sections based on wavelength, with gamma rays having the shortest wavelength and radio waves having the longest wavelength.
- The part of the electromagnetic spectrum that we can see using our naked eyes is called the visible light spectrum.
- In order of frequency, the radio waves have the lowest frequency while gamma rays have the largest frequency.
<h3>General characteristics of electromagnetic waves </h3>
- They travel with the speed of light (3.0 x 10^8 m/s)
- They possess energy that is given by; E =hf, where h is the plank’s constant and f is the frequency.
- They are transverse in nature, and therefore, the wavelength is measured between successful crests or troughs.
- They can travel through vacuum
Keywords: Electromagnetic spectrum, electromagnetic waves.
<h3>Learn more about: </h3>
Level: High school
Subject: Physics
Topic: Electromagnetic spectrum
It's C, with the 2/7/4/6 in front of each reactant and product.
Answer:
Explanation: Here we have given a direct equation . There for no need to worry .
P = I²×R
P = (12)² ×100
P = 14400W = 14.4 kW
For second one
P = I² ×R
200 = I²×150
I = √200/150
I = 1.15 A
