Question

Two 4.952 cm by 4.952 cm plates that form a parallel-plate capacitor are charged to +/- 0.576 nC. What is the electric field strength inside the capacitor if the spacing between the plates is 2.97 mm?

Answer 1

In order to solve this question, we will need to know the E-field of a capacitor

E = sigma/epsilon naught

To find sigma (charge density), we will need to divide the total charge by the area

sigma = (.576 x 10^-9)/(4.952x10^-2)^2 = 2.34 x 10^-7

E = 2.34 x 10^-7/ (8.85x10^-12) = 26541.04 V/m