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jeka57 [31]
4 years ago
9

Which part of the ear receives the signal from the cochlea and transmits it to the brain?

Physics
2 answers:
iogann1982 [59]4 years ago
8 0
Its b cochlea is the part of the ear is used for hearing
bazaltina [42]4 years ago
6 0

Im pretty sure it would be A) auditory nerve

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a 3.00 kg object undergoes an acceleration given by a = (2.00 i + 5.00 j) m/s^2 find the resultant force acting on the object an
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F = m.a

F = 3(2 I + 5 j)

F = 6i + 15j is resultant force

Magnitude force = √6+15 = √21

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3 years ago
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What is the potential energy of a 2,000-kg car parked at the top of a 30-m hill?
babymother [125]
Potential energy is a relative measure, so the answer is dependent on the assumptions we make. The potential energy in the car is going to be gravitational potential energy(PE). PE = mgh, where m is the mass, g is 9.8 m/s^2, and h is the height. So PE = 2000*9.8*h = 19600h. The final answer obviously depends on h. Most likely the problem is assuming that 30 meters under the top of the hill is considered 0 meters. Then h would be 30m and PE would equal 588 kJ.
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4 years ago
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A gull is flying horizontally 10.80 m above the ground at 6.00 m/s. The bird is carrying a clam in its beak and plans to crack t
UkoKoshka [18]

Answer:

v_y = 14.55 m/s

Explanation:

given,

height at which gull is flying = 10.80 m

speed of the gull = 6 m/s

acceleration due to gravity = 9.8 m/s²

Relative to the seagull, the x-speed is 0,

because the seagull has the same x-speed.

Only the y-speed counts:

v_y^2 = u^2 + 2 g h

v_y^2 = 0^2 + 2 g h

v_y = \sqrt{2gh}

v_y = \sqrt(2\times 9.8 \times 10.8)  

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v_y = 14.55 m/s

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8 0
3 years ago
What is the specific heat of the masses in this experiment? Infer the substance the masses are made of and explain your inferenc
Liono4ka [1.6K]

The metal whose specific heat capacity is close to the obtained value is aluminum.

<h3>What is specific heat capacity</h3>

The specific heat capacity of an object is the heat required to raise a unit mass of the substance by 1 kelvin.

Q= mc\Delta \theta

where;

  • c is the specific heat capacity
  • Δθ is change in temperature

Let the mass of the water = 50 g

mass of the metal for this first trial = 50 g

The heat gained by the water is calculated as follows

Q = 50 \times 4.184 \times 8.4\\\\Q = 1757.28 \ J

Specific heat capacity of the metal for the first trial is calculated as follows;

Heat gained by water = Heat lost by metal

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Specific heat capacity of the metal for the second trial;

mass of metal = 200 - mass of water = 150 g

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Specific heat capacity of the metal for the third trial;

C_3 = \frac{1757.28}{250 \times 20.8} = 0.34\ J/g^oC

Specific heat capacity of the metal for the fourth trial;

C_4 = \frac{1757.28}{350 \times 25.4} = 0.19\ J/g^oC

Specific heat capacity of the metal for the fifth trial;

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Average specific heat capacity

C = \frac{4.184 + 0.77 + 0.34+ 0.19 + 0.13 }{5} = 1.12 \ J/g^oC = 1120 J/kg^oC

The metal whose specific heat capacity is close to the above value is aluminum.

Learn more about specific heat capacity here: brainly.com/question/16559442

8 0
2 years ago
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3 years ago
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