B. so light can shine through it from below.
The term that describes the amount of energy transported past a given area of the medium per unit time would be "intensity." In addition, the formula for computing intensity would be:
Intensity = Energy / (Time * Area)
It can be implied that the wave would be more intense when its energy transfer rate gets increased and vibration amplitudes also increases.
Hello
1) First of all, since we know the radius of the wire (

), we can calculate its cross-sectional area

2) Then, we can calculate the current density J inside the wire. Since we know the current,

, and the area calculated at the previous step, we have

3) Finally, we can calculate the electric field E applied to the wire. Given the conductivity

of the aluminium, the electric field is given by
Answer:
A quick way of describing density is to describe an object as heavy or light for its size. Pumice stone, unlike regular rock, does not sink in water because it has a low density. An ironwood branch is very dense and sinks in water.
Hope that helps. x
Answer:
<em>d. The sail should be reflective because in this case the momentum transferred to the sail per unit area per unit time is larger than for absorbing sail, therefore the radiation pressure is larger for the reflective sail.</em>
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Explanation:
Let us take the momentum of a photon unit as u
we know that the rate of change of momentum is proportional to the force exerted.
For a absorbing surface, the photon is absorbed, therefore the final momentum is zero. From this we can say that
F = (u - 0)/t = u/t
for a unit time, the force is proportional to the momentum of the wave due to its energy density. Therefore,
F = u
For a reflecting surface, the momentum of the wave strikes the sail and changes direction. Since we know that the speed of light does not change, then the force is proportional to
F = (u - (-u))/t = 2u/t
just as the we did above, it becomes
F = 2u.
From this we can see that the force for a reflective sail is twice of that for an absorbing sail, and we know that the pressure is proportional to the force for a given area. From these, we conclude that <em>the sail should be reflective because in this case the momentum transferred to the sail per unit area per unit time is larger than for absorbing sail, therefore the radiation pressure is larger for the reflective sail.</em>
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