Question

Calculate each of the following in 0.185 mol of dipropyl ether, (C3H7)2O:

Answer 1

We have 6 moles of C (2*3=6), 14 moles of H (2*7=14) and 1 mol of O in 1 mol of (C₃H₇)₂O:

Therefore:
1 mol of (C₃H₇)₂O-------------6 moles of C
0.185 moles of (C₃H₇)₂O------    x

x=(0.185 moles * 6 moles)/1 mole=1.11 moles

Answer: there are 1.11 moles of C in 0.185 moles of dipropyl ether

1 mol of C-----------------6.022*10²³ atoms
1.11 moles of C------------  x

x=(1.11 moles of C *6.022*10²³ atoms)/1 mole of C=6.68 *10²³ atoms

Answer: there are 6.68*10²³ atoms of C in 0.185 moles of dipropyl ether.


1 mole of (C₃H₇)₂O-------------14 moles of H
0.185 moles of (C₃H₇)₂O------    x

x=(0.185 moles * 14 moles)/1 mole=2.59 moles


 there are 2.59 moles of H in 0.185 moles of dipropyl ether


1 mol -----------------------6.022*10²³ atoms
2.59 moles-----------------    x

x=(2.59 moles * 6.022*10²³ atoms)/1 mol=1.56*10²⁴ atoms

Answer: there are 1.56*10²⁴ atoms in 0.185 moles of dipropyl ether.


1 mol of (C₃H₇)₂O-------------1 moles of C
0.185 moles of (C₃H₇)---------    x

x=(0.185 moles *1mol)/1 mol=0.185 moles

Answer: there are 0.185 moles of O in 0.185 moles of dipropyl ether.