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natima [27]
3 years ago
9

Write a complete chemical formula, including physical state symbol, for each element listed below in its standard state. The fir

st row of the table has been completed for you.
element formula
iron Fe(s)
plutonium
lodine
helium
Chemistry
1 answer:
Irina18 [472]3 years ago
6 0

Explanation:

Plutonium

The symbol is Pu and it exists in the solid state.

The complete chemical formular is given as; Pu(s)

Iodine

The symbol is I and it exists exists as a lustrous, purple-black non-metallic solid at standard conditions

The complete chemical formular is given as; I(s)

Helium

The symbol is He and it exists in the gaseous state.

Te complete chemical formular is given as; He(g)

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Answer:

Temperature of the water

Explanation:

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Thus the respiration rate of the goldfish is the dependent variable because it is controlled by the temperature of the water and changes accordingly.

Summarily, the independent variable is the temperature of the water while the dependent variable is the respiration rate of the goldfish.

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What is the name of the compound that has the formula Li2SO3?
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The answer is A lithium sulfite
7 0
3 years ago
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Pls help me. Show proof on why it’s that answer.
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3 years ago
Be sure to answer all parts. Nitric oxide, NO·, is a radical thought to cause ozone destruction by a mechanism similar to that o
SIZIF [17.4K]

Answer:

See image attached and explanation

Explanation:

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6 0
3 years ago
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Burka [1]
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
5 0
2 years ago
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