Question

At 25 celsius, 1.00 ,ole of O2 was found to occupy a volume of 12.5 L at a pressure of 198 kPa. What value of the gas constant in L times kPa divided by mol Times K

Answer 1

Answer:

$R=8.301\frac{L*kPa}{mol*K}$

Explanation:

Hello,

In this case, assuming oxygen as an ideal gas, it is described by:

$PV=nRT$

Whereas the gas constant R is required, therefore, it is computed as shown below:

$R=\frac{PV}{nT} =\frac{198kPa*12.5L}{1.00mol*(25+273.15)K} \\\\R=8.301\frac{L*kPa}{mol*K}$

Best regards.