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svet-max [94.6K]
3 years ago
8

At 25 celsius, 1.00 ,ole of O2 was found to occupy a volume of 12.5 L at a pressure of 198 kPa. What value of the gas constant i

n L times kPa divided by mol Times K
Chemistry
1 answer:
mr Goodwill [35]3 years ago
4 0

Answer:

R=8.301\frac{L*kPa}{mol*K}

Explanation:

Hello,

In this case, assuming oxygen as an ideal gas, it is described by:

PV=nRT

Whereas the gas constant R is required, therefore, it is computed as shown below:

R=\frac{PV}{nT} =\frac{198kPa*12.5L}{1.00mol*(25+273.15)K} \\\\R=8.301\frac{L*kPa}{mol*K}

Best regards.

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Consider a pot of water at 100 C. If it took 1,048,815 J of energy to vaporize the water and heat it to 135 C, how many grams of
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Answer:

There was 450.068g of water in the pot.

Explanation:

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What mineral is the hardest known substance in nature?
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6CO2 + 6 H2O —&gt; C6H12O6 + 6O2
PilotLPTM [1.2K]

Answer:

The answer to your question is 0.5 moles

Explanation:

Data

moles of Glucose = ?

moles of carbon dioxide = 3

Balanced chemical reaction

                6CO₂  +  6H₂O   ⇒   C₆H₁₂O₆  +  6O₂

Process

To solve this problem, use proportions, and cross multiplication.

Use the coefficients of the balanced equation.

                6 moles of CO₂ ----------------- 1 mol of C₆H₁₂O₆

                3 moles of CO₂ ----------------    x

                    x = (3 x 1) / 6

-Simplification

                    x = 3/6

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