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svet-max [94.6K]
3 years ago
8

At 25 celsius, 1.00 ,ole of O2 was found to occupy a volume of 12.5 L at a pressure of 198 kPa. What value of the gas constant i

n L times kPa divided by mol Times K
Chemistry
1 answer:
mr Goodwill [35]3 years ago
4 0

Answer:

R=8.301\frac{L*kPa}{mol*K}

Explanation:

Hello,

In this case, assuming oxygen as an ideal gas, it is described by:

PV=nRT

Whereas the gas constant R is required, therefore, it is computed as shown below:

R=\frac{PV}{nT} =\frac{198kPa*12.5L}{1.00mol*(25+273.15)K} \\\\R=8.301\frac{L*kPa}{mol*K}

Best regards.

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Answer:

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>

what you have

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in theory

⋅

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actual

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−−−−−−−−−−−−−

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