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ankoles [38]
3 years ago
8

How are wavelength and frequency related?

Chemistry
2 answers:
emmasim [6.3K]3 years ago
5 0
Higher frequencies have shorter wavelengths and Lower frequencies have longer wavelengths. However one formula that relates them is Wavelength × Frequency = Speed of Light
Likurg_2 [28]3 years ago
4 0
Frequency can effect how tall or how long these Wavelengths are and their strength, therefore how "frequently" they will complete a wave-cycle.
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Which of the following best explains how subsoil becomes rich in minerals?
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Radiation is spontaneously emitted from hydrogen-3 nuclei, but radiation is not spontaneously emitted from hydrogen-l nuclei or
miv72 [106K]

Answer : Option 1) nuclei of H^{1} and nuclei of H^{2} only.


Explanation : Radiation is spontaneously emitted from nuclei of H^{3} because this isotope of hydrogen is highly radioactive as compared to other isotopes of hydrogen namely; nuclei of H^{1} and nuclei of H^{2}.


They have much stable nucleus as compared to nuclei of H^{3}.


The more it is unstable the more radiations will be emitted from its nucleus.

5 0
3 years ago
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6 0
3 years ago
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Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
galina1969 [7]

Answer:

\%\, yield\, \, SO_3=82.29

Explanation:

First write the balance eqation of chemical reaction:

2S(s) +3O_2(g) \rightarrow 2SO_3(g)

Remember writing any chemical reaction from its  elemetal form then write the elements in their natural form i.e. how that element exists in the nature here sulphur exists in solid monoatomic form in the nature and oxygen in gaseous diatomic form.

mass of oxygen given=5gram

mole of oxygen=5/32mol=0.16mol

mass of sulpher given=6gram

mole of sulpher=6/32mol=0.19mol

from the above balanced equaion;

2 mole of sulphur reacts with 3 mole Oxygen completely

1 mole of sulphur reacts with 1.5 mole Oxygen completely

0.19 mole of sulphur reacts with 1.5\times 0.19 i.e. 0.285 mole Oxygen completely.

but we have 0.16 mole so oxygen will be the limiting reagent and sulpher will be the excess reagent

so product will depend on the limiting reagent

from the balance equation

3 mole of sulpher gives 2 mole SO_3

1 mole of sulpher will give 2/3 mole SO_3

0.16 of sulpher will give 0.12 mole SO_3

mass of SO_3=9.6gram this is theoreical production of SO_3

and

actual production of SO_3 =7.9gram

\%\, yield   \,\, SO_3=\frac{Actual \,yield}{theoretical\, yield}\times 100

\%\, yield\, \, SO_3=\frac{7.9}{9.6} \times 100=82.29

\%\, yield\, \, SO_3=82.29

3 0
3 years ago
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