<span>this is a limiting reagent problem.
first, balance the equation
4Na+ O2 ---> 2Na2O
use both the mass of Na and mass of O2 to figure out how much possible Na2O you could make.
start with Na and go to grams of Na2O
55.3 gNa x (1molNa/23.0gNa) x (2 molNa2O/4 molNa) x (62.0gNa2O/1molNa2O) = 75.5 gNa2O
do the same with O2
64.3 gO2 x (1 molO2/32.0gO2) x (2 molNa2O/1 mol O2) x (62.0gNa2O/1molNa2O) = 249.2 g Na2O
now you must pick the least amount of Na2O for the one that you actually get in the reaction. This is because you have to have both reacts still present for a reaction to occur. So after the Na runs out when it makes 75.5 gNa2O with O2, the reaction stops.
So, the mass of sodium oxide is
75.5 g</span>
Answer:
- <u><em>C. The rate of sublimation of the NH₄CI crystals is equal to the rate of solidification of the NH₄CI vapors.</em></u>
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Explanation:
The question is garbled and the reactants and products do not match.
This is the correct question, assuming the products are correctly described:
"Consider the equilibrium system below.
If the system is at dynamic equilibrium, which statement is true?
- A. Sublimation of the NH₄CI crystals stops.
- B. Solidification of the NH₄CI vapors stops.
- C. The rate of sublimation of the NH₄CI crystals is equal to the rate of solidification of the NH₄CI vapors.
- D. The rate of sublimation of the NH₄CI crystals is higher than the rate of solidification of the NH₄CI vapors"
<h2>Solution</h2>
The left side of the equation shows solid<em> NH₄CI</em>. The right side shows gas <em>NH₄CI</em>.
Thus, the equation represents the <em>equilibrium</em> between the formation of <em>crystals</em> (solid) and <em>vapors </em>(gas) of the compound <em>NH₄CI</em>.
The change from solid state to gas state is represented by the <em>forward reaction </em>(fom left to the right). It is named sublimation.
The change from vapors to crystals (named deposition) is represented by the <em>reverse reaction</em> (from right to left).
<em>Dynamic equilibrium</em> means that the molecules continually form vapors and cristals at the same speed. Thus, the final result is that each the total number of molecules of vapors and the total number of molecules of crystals do not change.
In conclusion, <em>"The rate of sublimation of the NH₄CI crystals is equal to the rate of solidification of the NH₄CI vapors" (option C).</em>
Answer
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Explanation