Answer:
The vapor pressure in solution is 0,0051 atm
Explanation:
This is the formula for vapor pressure lowering, the colligative property.
P vapor = Pressure sv pure . Xsv
Where Xsv is data.
Xsv means Molar fraction (moles solvent/total n° moles)
Vapor pressure of water, pure is 17.5 mmHg
P vapor = 0,0313 atm . 0163
P vapor in solution = 0,0051 atm
Molar fraction does not have units
A solution will have less vapor pressure than that observed in the pure solvent.
Neutron or neutral and electran are positive
The a is 5 your welcome dude
Hey there,
Question :<span>If sulfur 34 undergoes alpha decay, what will it become?</span>
Answer: It becomes silicon-30.
Hope this helps :))
<em>~Top♥</em>
If my math is right, it should be around 4.33x10^23
To get this you need to find the atomic weight of MgI2, which is around 278. You divide the mass in grams by the atomic mass to find Moles, then you multiply the moles by Avogadros number: 6.022x10^23. Hope I was helpful
