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finlep [7]
3 years ago
9

A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is 19.78 nm. What is the total wi

dth of a crystal in millimeters 105 molecules across? Write your answer as a decimal.
Chemistry
1 answer:
kobusy [5.1K]3 years ago
6 0
1 nm = 0.000001 mm

105 * 19.78  * 0.000001 = 0.0020769 mm
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Which of the following two periods contain the same number of element?
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Answer:

4 and 6

Explanation:

Period 4 has 18 elements and so does period 6.

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Which is the least active family
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How many valence electrons does a helium atom have? what is the formula of the ion formed when potassium achieves noble-gas elec
OlgaM077 [116]

> How many valence electrons does a helium atom have?

The electron configuration of Helium is simply 1s2. We see that its outermost shell is the s shell and it contains 2 electrons, therefore the number of valence electrons is also 2.

 

> What is the formula of the ion formed when potassium achieves noble-gas electron configuration?

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4 years ago
How many grams of sulfur trioxide are produced 18 mol O2 react with sufficient sulfur? Show all your work S8 +12O 2&gt; 8SO3
SOVA2 [1]

Answer:

m_{SO_3}=2.31x10^4gSO_3

Explanation:

Hello!

In this case, since the reaction between sulfur and oxygen is:

S_8 +\frac{1}{2} O_2 \rightarrow 8SO_3

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7 0
3 years ago
g What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL
Pani-rosa [81]

The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2M was neutralized by 0.01 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 0.125 mL

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl (Stomach acid)

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.01M\\V_2=25mL

Putting values in above equation, we get:

1\times 2\times V_1=1\times 0.01\times 25\\\\V_1=\frac{1\times 0.01\times 25}{1\times 2}=0.125mL

Hence, the volume of HCl neutralized is 0.125 mL

3 0
4 years ago
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