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3 years ago

What is the term for a compound made from only two elements?

Physics

2 answers:

Vladimir79 [104]3 years ago

6 0

I believe it is binary.

makvit [3.9K]3 years ago

4 0

Answer:

Binary

Explanation:

When two compounds are made from specifically only of two elements, that compound is known as binary. Binary compounds can be of two types

1. where two elements are different and only one atom of each element would participate in compound making. some of the examples are:- sodium chloride(one sodium and one chlorine).

2. Where more than one atom of each element participate such as nitrous oxide(two atoms of nitrogen and one of oxygen).

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One way to ensure that the race ends up in a tie is to have the person who lost the original race run a shorter distance before

Vikki [24]

Answer:

The appropriate answer is "72.8 m".

Explanation:

Let the distance be "x".

As per the question, we get

⇒ $T_{Mia}=T_{Brandi}$

or,

⇒ $\frac{x}{13} +\frac{x}{7}=\frac{\80}{10} +\frac{80}{10}$

By taking L.C.M, we get

⇒ $\frac{20x}{91}=16$

By applying cross-multiplication, we get

⇒ $20x=1440$

⇒ $x=\frac{1456}{20}$

⇒ $=72.8\ m$

6 0

3 years ago

Question:

valkas [14]

Answer:

the answer is true.

Explanation:

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5 0

3 years ago

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Which statement describes the relationship of resistance and current? resistance is directly proportional to current because r =

Karolina [17]

Two different relationship resistance

6 0

2 years ago

Determine the initial velocity of the ball if it reaches a height of 15 meters.

jasenka [17]

Answer:

the initial velocity of the ball is 17.14 m/s

Explanation:

Given;

maximum height reached by the ball, h = 15 m

let the initial velocity of the ball = u

at maximum height, the final velocity of the ball is zero, v = 0

The initial velocity of the ball is calculated by using the following upward motion kinematic equation;

v² = u² - 2gh

0 = u² - 2(9.8 x 15)

u² = 294

u = √294

u = 17.14 m/s

Therefore, the initial velocity of the ball is 17.14 m/s

4 0

3 years ago

The system below uses massless pulleys and ropes. The coefficient of friction is μ. Assume that M1 and M2 are sliding. Gravity i

Archy [21]

Explanation:

Using Newtons second law on each block

F = m*a

Block 1

$T_{1} - u*g*M_{1} = M_{1} *a \\\\T_{1} = M_{1}*(a + u*g) ... Eq1$

Block 2

$T_{2} - u*g*M_{2} = M_{2} *a \\\\T_{2} = M_{2}*(a + u*g) ... Eq2$

Block 3

$- (T_{1} + T_{2} ) + g*M_{3} = M_{3} *a \\\\T_{1} + T_{2} = M_{3}*( -a + g) ... Eq3$

Solving Eq1,2,3 simultaneously

Divide 1 and 2

$\frac{T_{1} }{T_{2}} = \frac{M_{1}*(a+u*g)}{M_{2}*(a+u*g)} \\\\\frac{T_{1} }{T_{2}} = \frac{M_{1} }{M_{2} }\\\\ T_{1} = \frac{M_{1} *T_{2} }{M_{2} } .... Eq4$

Put Eq 4 into Eq3

$T_{2} = \frac{M_{3}*(g-a) }{1+\frac{M_{1} }{M_{2} } } ...Eq5$

Put Eq 5 into Eq2 and solve for a

$a = \frac{M_{3}*g -u*g*(M_{1} + M_{2}) }{M_{1} + M_{2} + M_{3} } .... Eq6$

Substitute back in Eq2 and use Eq4 and solve for T2 & T1

$T_{2} = M_{2}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\T_{1} = M_{1}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\$

5 0

4 years ago